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我的PHP返回值时，值传递给它我检查了铬的插件POSTMAN ...我无法找出问题：\ 这是我的代码我试图从我的Android代码发送值（这是好的）来更新数据库： -我的PHP返回值为空时值传递给它
<?php
$response = array();
// check for required fields
if (isset($_POST['id']) && isset($_POST['company']) && isset($_POST['date']) &&
isset($_POST['time']) && isset($_POST['ten']) && isset($_POST['twelve']) &&
isset($_POST['aggregate']) && isset($_POST['backlog']) && isset($_POST['pending']) &&
isset($_POST['branch'])) {
$cid = $_POST['id'];
$company = $_POST['company'];
$date = $_POST['date'];
$time = $_POST['time'];
$ten = $_POST['ten'];
$twelve = $_POST['twelve'];
$aggregate = $_POST['aggregate'];
$backlog = $_POST['backlog'];
$pending = $_POST['pending'];
$branch = $_POST['branch'];
// include db connect class
require_once __DIR__ . '/db_connect.php';
// connecting to db
$db = new DB_CONNECT();
// mysql update row with matched pid
$result = mysql_query("UPDATE companies SET company = '$company', date = '$date', time
= '$time' ten = '$ten', twelve = '$twelve',aggregate = '$aggregate', backlog =
'$backlog', pending = '$pending', branch = '$branch' WHERE id = $cid");
// check if row inserted or not
if ($result) {
// successfully updated
$response["success"] = 1;
$response["message"] = "Company successfully updated.";
// echoing JSON response
echo json_encode($response);
} else {
}
} else {
// required field is missing
$response["success"] = 0;
$response["message"] = "Required field(s) is missing";
// echoing JSON response
echo json_encode($response);
}
?>
'//连接到数据库 $ DB =新DB_CONNECT（）;'这看起来很奇怪 –
OOF。你需要使用准备好的语句。这是不安全的。请参阅[这里]（http://stackoverflow.com/questions/60174/how-can-i-prevent-sql-injection-in-php?rq=1） –
请使用参数化查询与PDO;你的代码很容易发生SQL注入。 – mc10