2016-01-21 78 views
1

我从另一个计算器问题bash脚本让我所有的串行连接的设备:输出解析到Rails

#!/bin/bash 
for sysdevpath in $(find /sys/bus/usb/devices/usb*/ -name dev); do 
    (
     syspath="${sysdevpath%/dev}" 
     devname="$(udevadm info -q name -p $syspath)" 
     [[ "$devname" == "bus/"* ]] && continue 
     eval "$(udevadm info -q property --export -p $syspath)" 
     [[ -z "$ID_SERIAL" ]] && continue 
     echo "{name: '/dev/$devname', id_serial: '$ID_SERIAL'}" 
    ) 
done 

我试图把它解析为对象的数组,以迭代和将它们显示在Rails视图中。输出是这样的:

{name: '/dev/input/event16', id_serial: 'Logitech_USB_Receiver'} 
{name: '/dev/input/mouse2', id_serial: 'Logitech_USB_Receiver'} 
{name: '/dev/hidraw0', id_serial: 'Logitech_USB_Receiver'} 
{name: '/dev/usb/hiddev3', id_serial: 'Logitech_USB_Receiver'} 
{name: '/dev/input/event17', id_serial: 'Logitech_USB_Receiver'} 
{name: '/dev/hidraw1', id_serial: 'Logitech_USB_Receiver'} 
{name: '/dev/input/event15', id_serial: 'SunplusIT_INC._Integrated_Camera'} 
{name: '/dev/media0', id_serial: 'SunplusIT_INC._Integrated_Camera'} 
{name: '/dev/video0', id_serial: 'SunplusIT_INC._Integrated_Camera'} 

在这个Rails的控制台输出:

2.2.4 :001 > `./lib/scripts/get_serial.sh` 
=> "{name: '/dev/input/event16', id_serial: 'Logitech_USB_Receiver'}\n{name: '/dev/input/mouse2', id_serial: 'Logitech_USB_Receiver'}\n{name: '/dev/hidraw0', id_serial: 'Logitech_USB_Receiver'}\n{name: '/dev/usb/hiddev3', id_serial: 'Logitech_USB_Receiver'}\n{name: '/dev/input/event17', id_serial: 'Logitech_USB_Receiver'}\n{name: '/dev/hidraw1', id_serial: 'Logitech_USB_Receiver'}{name: '/dev/media0', id_serial: 'SunplusIT_INC._Integrated_Camera'}\n{name: '/dev/video0', id_serial: 'SunplusIT_INC._Integrated_Camera'}\n" 

,所以我试图解析它像这样在我的控制器:

def index 
    @devices = `./lib/scripts/get_serial.sh`.strip.gsub(" ","").split("\n") 
end 

,如果我做@devices[0]的结果是:=> "{name:'/dev/input/event16',id_serial:'Logitech_USB_Receiver'}"

最后,在视图:

<ul> 
    <% @devices.each do |device| %> 
    <li><%= device %> </li> 
    <% end %> 
</ul> 

显示所有设备,但如果我这样做<%= device.name %>我得到一个错误或<%= device['name'] %>我得到了这个词“名”。

我的问题很简单。有没有更好的方法来做到这一点,并将:name:id_serial作为典型变量(迭代数组并打印它们)?

回答

1

相反的:

@devices = `./lib/scripts/get_serial.sh`.strip.gsub(" ","").split("\n") 

尝试使用:

@devices = `./lib/scripts/get_serial.sh`.split("\n").map {|hash_string| eval(hash_string)} 

更多的解释,你应该检查How do I convert a String object into a Hash object?

+0

不幸的是'设备[ '名']'在视图中显示为空/空白值。 – ftshtw

+0

@ChrisV。为什么它应该呢?试试''device [:name]'' –

+0

如果你不解释这一点,我会辞去工作,成为面包师或垃圾回收员。 – ftshtw