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Question

Ruby代码是：

a = [] 
    h = {} 
    2.times.each do |i| 
     %w(a b c).each do |x| 
     h[x] = x + i.to_s 
     end 
     a << h 
    end 

结果是：

a = [{"c"=>"c1", "b"=>"b1", "a"=>"a1"}, {"c"=>"c1", "b"=>"b1", "a"=>"a1"}] 

但我希望的结果是：

a = [{"c"=>"c0", "b"=>"b0", "a"=>"a0"}, {"c"=>"c1", "b"=>"b1", "a"=>"a1"}] 

谁可以帮助me.thx

Answer 1

后a << h你必须做h = {}。这是因为您正在为h分配一个新对象，以便它不覆盖以前的值。

Answer 2

[补充回答]您是否熟悉functional programming的原理？

(0..1).map { |n| Hash[("a".."c").map { |c| [c, "#{c}#{n}"] }] } 
#=> {"a"=>"a0", "b"=>"b0", "c"=>"c0"}, {"a"=>"a1", "b"=>"b1", "c"=>"c1"}]