有一个限制,而使用Julian dates
,它的范围从1 to 5373484
。这就是为什么如果你把值5373484
后,它会抛出你的错误如下图所示:
ORA-01854: julian date must be between 1 and 5373484
为了满足上述问题,创建一个函数,并与J-> JSP小动作,你可以取期望的结果。
CREATE OR REPLACE FUNCTION spell_number (p_number IN NUMBER)
RETURN VARCHAR2
AS
TYPE myArray IS TABLE OF VARCHAR2 (255);
v_decimal PLS_INTEGER;
l_str myArray
:= myArray ('',
' thousand ',
' million ',
' billion ',
' trillion ',
' quadrillion ',
' quintillion ',
' sextillion ',
' septillion ',
' octillion ',
' nonillion ',
' decillion ',
' undecillion ',
' duodecillion ');
l_num VARCHAR2 (50) DEFAULT TRUNC (p_number);
l_return VARCHAR2 (4000);
BEGIN
FOR i IN 1 .. l_str.COUNT
LOOP
EXIT WHEN l_num IS NULL;
IF (SUBSTR (l_num, LENGTH (l_num) - 2, 3) <> 0)
THEN
l_return :=
TO_CHAR (TO_DATE (SUBSTR (l_num, LENGTH (l_num) - 2, 3), 'J'),
'Jsp')
|| l_str (i)
|| l_return;
END IF;
l_num := SUBSTR (l_num, 1, LENGTH (l_num) - 3);
END LOOP;
v_decimal := 100* (p_number -TRUNC(p_number)) ;
IF v_decimal>0 THEN
RETURN l_return ||' Dollars AND '||TO_CHAR (TO_DATE (v_decimal, 'j'), 'jsp')|| ' Cents';
ELSE
RETURN l_return ||' Dollars' ;
END IF;
END;
/
select spell_number(122344343444444.23) from dual;
输出:
一百二十两万亿三四四十亿三百四十三亿元四百四十四个一千四百四十四美元和23美分Blog Link
感谢Noel..It正在为我工作...... – user2090701 2013-05-13 09:17:09
@noel:使用Julian日期有一个限制,范围从1到5373484.这就是为什么如果你把值放在5373484之后,它会抛出你一个错误如下所示:'ORA-01854:朱利安日期必须在1之间和5373484',如问题所述,数字可以有18个数字,那么这种情况是可能的 – 2013-05-13 09:58:28
@GauravSoni:oops ... – Noel 2013-05-13 10:03:42