0
我正在尝试按字母顺序排列用户输入,最多10,000个单词,最大长度为25个单词。我正在使用“停止”来提前终止用户输入,这会使我陷入一些问题。下面为输出当前程序的结果,当我尝试输入你好停止按字典返回记忆字符对用户输入进行排序?
▒l▒
0▒l▒
A{▒
e▒
▒&
▒▒
▒▒
▒▒
▒▒
▒l▒
▒l▒
▒▒;
▒Se▒
▒
▒
▒
▒
▒!
Ќl▒
▒
▒
▒
▒.X
▒
我假定这是与我的内存分配做,但我也不太清楚,但没有找到对此一些答案。任何帮助,将不胜感激,下面是我的代码
#include<stdio.h>
#include <string.h>
//for using tolower
#include <ctype.h>
int main() {
int i, k, j;
char abc[25];
const char *stop = "stop";
char *p; //using for lowercase
//using 2d array for max of 10,000 words, max size of words 25
char str[10000][25], temp[25];
printf("Enter up to 10000 words, type stop to enter the current words:\n");
while (strncmp(abc, "stop", 5) != 0) {
scanf("%s", abc);
}
//for (i = 0; i < 10000; ++i)
//scanf("%s[^\n]", str[i]);
for (i = 0; i < 10000; ++i)
for (k = i + 1; k < 10000; ++k) {
//comparing two strings using strcmp() function is used
//using strcpy() to copy string to a temp
if (strcmp(str[i], str[k]) > 0) {
strcpy(temp, str[i]);
strcpy(str[i], str[k]);
strcpy(str[k], temp);
}
}
//using pointer to converting to lowercase
//src: https://www.daniweb.com/programming/software-development/threads/57296/how-does-one-tolower-an-entire-string
for (p = str; *p != '\0'; p++)
*p = (char) tolower(*p);
//printing words in lexi order
printf("\nWords in lexicographical order: \n");
for (i = 0; i < 10000; ++i) {
puts(str[i]);
}
printf("WARNING: Words longer than 25 in length were ignored. \n");
return 0;
}
不保存输入将字符串转换为'str'数组。 – BLUEPIXY
另外,'while'循环首次运行时,'abc'没有初始化。在发布问题之前,打开您的编译器警告并修复所有这些警告。并学会使用调试器。如果您使用过调试器,问题应该清楚。 – kaylum
@WhozCraig那讽刺真的有必要吗?另外,'datum'在你的句子中不正确。它应该是复数的“数据”。 – DIMMSum