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我对C++比较陌生,所以请有怜悯。我试图在二维数组40 * 20中指定“矢量”的开始和结束。但是“b”不会被放在最后2个循环中。最后,我想显示2个向量,第二个向量从[0] [0]开始,并沿着与用户输入的方向相同的方向。我也不知道如何让b从线的起点到线的终点,而不仅仅是起点和终点。但主要问题是x不随b改变。C++,控制台,cout 2D矢量数组
感谢您的帮助。
#include "stdafx.h"
#include <iostream>
#include <cstdlib>
#include <time.h>
using namespace std;
int vectorsx;
int vectorsy;
int vectorendx;
int vectorendy;
char display[40][40];
char row;
char column;
typedef struct
{
double x;
double y;
}punkt;
typedef struct
{
punkt PA;
punkt PE;
}vector;
void query()
{
cout << "Startpunkt x:";
cin >> vectorsx;
cout << "Startpunkt y:";
cin >> vectorsy;
cout << "Endpunkt x:";
cin >> vectorendx;
cout << "Endpunkt y:";
cin >> vectorendy;
}
int main()
{
query();
vector v;
v.PA.x = vectorsx;
v.PA.y = vectorsy;
v.PE.x = vectorendx;
v.PE.y = vectorendy;
vector v2;
v2.PA.x = 0;
v2.PA.y = 0;
v2.PE.x = v.PE.x - v.PA.x;
v2.PE.y = v.PE.y - v.PA.y;
for (int row = 0; row < 20; row++)
{
for (int column = 0; column < 40; column++)
{
display[row][column] = 'x';
}
}
for (int row = 0; row < 20; row++)
{
for (int column = 0; column < 40; column++)
{
cout << display[row][column];
}
cout << endl;
}
for (row = 0; row < 20; row++)
{
for(column = 0; column < 40;column++)
{
display[vectorsx][vectorsy] = 'b';
}
}
for (row = 0; row < 20; row++)
{
for (column = 0; column < 40; column++)
{
display[vectorendx][vectorendy] = 'b';
}
}
system("Pause");
return 0;
}
大声笑我是这样一个小孩非常感谢你。 –
它现在有效,没有它的循环工作,也感谢tou Joachim! –