选择哪里不工作 - 用户ID

Question

我工作的脚本，但这不起作用，我不知道为什么。

所以啊，这是代码，谁不工作：

try { 
    $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password); 
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 
    $stmt = $conn->prepare("SELECT frage, status, antwort FROM kontakt WHERE userID = " . intval($row['userID']); 
    $stmt->execute(); 

    // set the resulting array to associative 
    $result = $stmt->setFetchMode(PDO::FETCH_ASSOC); 
    foreach(new TableRows(new RecursiveArrayIterator($stmt->fetchAll())) as $k=>$v) { 
     echo $v; 
    } 
} 

我想这是因为("SELECT frage, status, antwort FROM kontakt WHERE userID = " . intval($row['userID']);

我希望你能帮帮我！

这是全码：

<?php 
session_start(); 
require_once 'class.user.php'; 
$user_home = new USER(); 

if(!$user_home->is_logged_in()) 
{ 
     $user_home->redirect('index.php'); 
} 

$stmt = $user_home->runQuery("SELECT * FROM tbl_users WHERE userID=:uid"); 
$stmt->execute(array(":uid"=>$_SESSION['userSession'])); 
$row = $stmt->fetch(PDO::FETCH_ASSOC); 

?> 

<?php include_once 'header.php'; ?> 

     <div id="wrapper"> 

     <div class="container"> 

      <div class="page-header"> 
      <h3>Kevin-Bank.ch - Bank & Shop und bald vieles mehr!</h3> 
      </div> 

      <form method="post" action=""> 
       <label>Minecraft Name:</label> 
       <input disabled class="form-control" type="text" name="jajaj" value="<?php echo $row['userName']; ?>" required/> 
       <input class="hidden" type="text" name="name" value="<?php echo $row['userName']; ?>" /> 
       <label>Email Adresse:</label> 
       <input disabled class="form-control" type="text" name="jajajja" value="<?php echo $row['userEmail']; ?>" required/> 
       <input class="hidden" type="text" name="email" value="<?php echo $row['userEmail']; ?>" /> 
       <label>Frage:</label> 
       <textarea class="form-control" rows="5" name="frage" required="required"></textarea> 
       <br > 
       <button type="submit" name="senden" class="btn btn-md btn-info">Senden</button> 
       <p></p> 

     </div> 
     </div> 

<?php 
if(isset($_POST["senden"])){ 
$hostname='localhost:3306'; 
$username='****'; 
$password='*****!'; 

try { 
    $dbh = new PDO("mysql:host=$hostname;dbname=*****",$username,$password); 

    $dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); // <== add this line 


$sql = "INSERT INTO kontakt (name, email, frage) 
VALUES ('".$_POST["name"]."','".$_POST["email"]."','".$_POST["frage"]."')"; 


if ($dbh->query($sql)) { 
    echo "<script type= 'text/javascript'>alert('Frage wurde gesendet, in kürzeste Zeit beantworten wir ihre Frage!');</script>"; 
} 
else{ 
    echo "<script type= 'text/javascript'>alert('Frage konnte nicht gesendet werden, bitte melde dich bei Kevin4K!');</script>"; 
} 

    $dbh = null; 
    } 
catch(PDOException $e) 
    { 
    echo $e->getMessage(); 
    } 

} 
?> 
<div class="container"> 
    <h2 align='center'>Die letzten Fragen von dir</h2><hr> 
<?php 
echo "<table align='center' class='table'>"; 
echo "<thead><tr><th>Frage</th><th>Status</th><th>Antwort</th></tr></thead>"; 

class TableRows extends RecursiveIteratorIterator { 
    function __construct($it) { 
     parent::__construct($it, self::LEAVES_ONLY); 
    } 

    function current() { 
     return "<td>" . parent::current(). "</td>"; 
    } 

    function beginChildren() { 
     echo "<tr>"; 
    } 

    function endChildren() { 
     echo "</tr>" . "\n"; 
    } 
} 

$servername = "localhost:3306"; 
$username = "kevin"; 
$password = "madarmadar22!"; 
$dbname = "mohammada_kevin"; 

$id = intval($_GET['userID']); 

try { 
    $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password); 
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 
    $stmt = $conn->prepare("SELECT frage, status, antwort FROM kontakt WHERE userID = " . intval($row['userID']); 
    $stmt->execute(); 

    // set the resulting array to associative 
    $result = $stmt->setFetchMode(PDO::FETCH_ASSOC); 
    foreach(new TableRows(new RecursiveArrayIterator($stmt->fetchAll())) as $k=>$v) { 
     echo $v; 
    } 
} 
catch(PDOException $e) { 
    echo "Error: " . $e->getMessage(); 
} 
$conn = null; 
echo "</table></div>"; 
?> 

    </div> 

    </div> 

    <script src="asets/jquery-1.11.3-jquery.min.js"></script> 
    <script src="asets/js/bootstrap.min.js"></script> 


</body> 
</html> 

Answer 1

语法错误在这行：

$stmt = $conn->prepare("SELECT frage, status, antwort FROM kontakt WHERE userID = " . intval($row['userID']); 

更改为：

$stmt = $conn->prepare("SELECT frage, status, antwort FROM kontakt WHERE userID = " . intval($row['userID'])); 

缺少 '）'

Answer 2

你在第一种状态下缺少一个支架它应该是$stmt = $conn->prepare("SELECT frage, status, antwort FROM kontakt WHERE userID = " . intval($row['userID']));