-1
谁能帮我这个代码吗?下一个和以前的链接不工作寻呼下一个和以前的链接不工作!
$limit=20;
mysql_connect("localhost","root","");
mysql_select_db("autoschool") or die("Unable to select database");
$query = "select * from student";
$numresults=mysql_query($query);
$numrows=mysql_num_rows($numresults);
if ($numrows == 0)
{
echo "empty";
}
if (empty($s)) {
$s=0;
}
$query .= " limit $s,$limit";
$result = mysql_query($query) or die("Couldn't execute query");
$count = 1 + $s ;
while ($row= mysql_fetch_array($result)) {
$title = $row["id"];
echo "$count.)$title"."
" ;
$count++ ;
}
$currPage = (($s/$limit) + 1);
echo "
";
if ($s>=1) { // bypass PREV link if s is 0
$prevs=($s-$limit);
print " <<
Prev 10  ";
}
$pages=intval($numrows/$limit);
if ($numrows%$limit) {
$pages++;
}
if (!((($s+$limit)/$limit)==$pages) && $pages!=1) {
$news=$s+$limit;
echo " Next 20 >>";
}
$a = $s + ($limit) ;
if ($a > $numrows) { $a = $numrows ; }
$b = $s + 1 ;
echo "
Showing results $b to $a of $numrows
";
在行之前4个空格使其显示格式正确。 – scragar 2009-11-21 12:52:32
代码不清楚。 echo语句中有一些不恰当的字符。也许这就是为什么这些链接不起作用。 – pavium 2009-11-21 12:54:09