平均负数python

Question

我需要一个文件中的3个向量的平均值。这是文件：

7.308017466911098700e-01 -5.497365223199360800e-01 -1.324069582379517300e-01 
7.142889846599955700e-01 -5.300077858149733200e-01 -1.214793135300424200e-01 
7.142889846599955700e-01 -5.300077858149733200e-01 -1.214793135300424200e-01 
7.142889846599955700e-01 -5.300077858149733200e-01 -1.214793135300424200e-01 
6.835045107440532700e-01 -4.980522174917749700e-01 -1.158373119954510000e-01 
6.835045107440532700e-01 -4.980522174917749700e-01 -1.158373119954510000e-01 
6.835045107440532700e-01 -4.980522174917749700e-01 -1.158373119954510000e-01 
6.835045107440532700e-01 -4.980522174917749700e-01 -1.158373119954510000e-01 
7.440304087049756100e-01 -5.568396579851897500e-01 -1.014631831749943100e-01 
7.021751417881535500e-01 -6.350121671924353600e-01 -5.052342816781073300e-02 

正如你所看到的第二列只包含负数。当我尝试平均代码：

with open(myfile) as fin: 
    for line in fin: 
     vec.append(float(line.split()[1])) 
    mean1=np.mean(vec) 
    print mean1 

我得到一个正数！

有没有numpy.mean的东西？

Answer 1

我测试过了，代码按预期工作。确保vec在开始时为空。