在sql server2005中使用sql查询从当前日期的出生日期发现年龄？

Question

从使用sql查询的当前日期的出生日期年份发现年龄？

Answer 1

Drop table Bird; 

CREATE TABLE Bird (
    name VARCHAR(20), 
    owner VARCHAR(20), 
    species VARCHAR(20), 
    sex CHAR(1), 
    birth DATE, 
    death DATE 
); 



INSERT INTO Bird VALUES ('BlueBird','Joe','Car','f','1999-03-30',NULL); 
INSERT INTO Bird VALUES ('RedBird','Yin','Bus','m','1979-04-30',NULL); 
INSERT INTO Bird VALUES ('RedBird','Yin','Bus','m','1998-01-30',NULL); 



SELECT name, birth, CURDATE(), 
     (YEAR(CURDATE())-YEAR(birth)) 
     - (RIGHT(CURDATE(),5)<RIGHT(birth,5)) 
     AS age 
     FROM Bird; 

Answer 2

您可能希望参考由史蒂夫·卡斯占了一些优势情况下，包括闰年开发的well known solution。这是供参考：

DECLARE @birthdate SMALLDATETIME, @endDate SMALLDATETIME 
SET @birthdate = '19791204' 
SET @endDate = GETDATE() 

SELECT DATEDIFF 
( 
    YEAR, 
    @birthdate, 
    @endDate 
) - CASE 
    WHEN 100 * MONTH(@endDate) + DAY(@endDate) 
    < 100 * MONTH(@birthdate) + DAY(@birthdate) 
    THEN 1 ELSE 0 END 

Answer 3

DECLARE 
@dob DATETIME 
BEGIN 
SET @dob = '19791204' -- set your birthday in datetime.. 
SELECT DATEDIFF(YEAR,@dob,GETDATE()) AS AGE 
-- if you do it reverse : DATEDIFF(YEAR,GETDATE(),@dob,) you will get negative 
-- refer : http://msdn.microsoft.com/en-us/library/ms189794.aspx 
END