2016-07-22 54 views
0

我在基表test1上创建了一个视图,并且在创建时添加了两列。试图在视图创建中添加更新

create or replace force view abc1 as (select A.*,cast(NULL as timestamp) AS new1,cast(NULL as varchar2) AS new2 from test1 A); 

所以创建视图后,它具有数据如下:

SELECT * FROM ABC1;

TT   | TT_C2     | TT_DAY  | TT_HOURLY  | OC | SEV  | EXTRACOL | IDENTIFIER | NEW1 | NEW2 
1468309423961 | 2016-07-12 07:43:43.0 | 12-07-2016 | 12-07-2016 07 | abc | Critical | asdf  | 1   | null | null 
1468922692865 | 2016-07-19 10:04:52.0 | 19-07-2016 | 19-07-2016 10 | abc | Critical | asdf  | 1   | null | null 
1568308812001 | 2019-09-12 17:20:12.0 | 12-09-2019 | 12-09-2019 17 | abc1 | Major | asdf  | 1   | null | null 
1468308812001 | 2016-07-12 07:33:32.0 | 12-07-2016 | 12-07-2016 07 | abc2 | Minor | asdf  | 1   | null | null 
1468308815972 | 2016-07-12 07:33:35.0 | 12-07-2016 | 12-07-2016 07 | abc | Critical | asdf  | 1   | null | null 

现在我试图更新名new1列是timestmap数据类型的,但我不能更新,因为一定的局限性的看法..

update view abc1 set new1 = DATEADD('SECOND', (TT)/1000), DATE '1970-01-01') WHERE new1 IS NULL; 

错误来是::

Syntax error in SQL statement "UPDATE ABC1 SET NEW1 = DATEADD('SECOND', (TT)/1000)[*], DATE '1970-01-01') WHERE NEW1 IS NULL "; expected "[, ::, *, /, %, +, -, ||, ~, !~, NOT, LIKE, REGEXP, IS, IN, BETWEEN, AND, OR, ,"; SQL statement: 
update abc1 set new1 = DATEADD('SECOND', (TT)/1000), DATE '1970-01-01') WHERE new1 IS NULL [42001-176] 

如何将我的更新“new1”列查询添加到我的视图创建中,以便仅在视图创建期间解决此问题。

这是我的基本表::

TT   | TT_C2     | TT_DAY  | TT_HOURLY  | OC | SEV  | EXTRACOL | IDENTIFIER 
1468309423961 | 2016-07-12 07:43:43.0 | 12-07-2016 | 12-07-2016 07 | abc | Critical | asdf  | 1 
1468922692865 | 2016-07-19 10:04:52.0 | 19-07-2016 | 19-07-2016 10 | abc | Critical | asdf  | 1 
1568308812001 | 2019-09-12 17:20:12.0 | 12-09-2019 | 12-09-2019 17 | abc1 | Major | asdf  | 1 
1468308812001 | 2016-07-12 07:33:32.0 | 12-07-2016 | 12-07-2016 07 | abc2 | Minor | asdf  | 1 
1468308815972 | 2016-07-12 07:33:35.0 | 12-07-2016 | 12-07-2016 07 | abc | Critical | asdf  | 1 

在此先感谢!

关于

回答

1

理想情况下,您不应该更新视图。

根据您的要求,您必须使用包装来获取列(即通过select选择)。

create or replace force view abc7 as (select tt,oc,sev, converted_event_time,formatdatetime(converted_event_time,'d-MM-yyyy HH') ,formatdatetime(converted_event_time,'d-MM-yyyy') AS event_time_day from (select tt,oc,sev,DATEADD('SECOND', (tt)/1000, DATE '1970-01-01') AS converted_event_time from test1)); 

希望你会发现这个答案有用。

+0

中提琴,多数民众赞成在..非常感谢 – Apurv

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