我正在研究C++项目,其中一个功能是采用中缀表示法中的代数表达式,将其转换为修补后符号并解决该问题。转换到后期修复工作正常,我相信我的代码用于评估后修复表达式将按预期工作,但由于错误C2280,我无法编译。下面是定位后评估的代码(我很新的C++,因此任何人与它经历,当他们看到有多穷,这可能是可以有一个动脉瘤):C++错误C2280:尝试引用已删除的函数
string EvaluatePostfix(string expression) {
double num;
double leftOp;
double rightOp;
string leftOpString;
string rightOpString;
stringstream numberToPush;
double tempResult;
string tempResultString;
stringstream tempResultSS;
stack<stringstream> S;
string finalResultString;
for (std::size_t i = 0, l = expression.size(); i < l; ++i) {
if (expression[i] == '=')
break;
else if (isalnum(expression[i])) { //If the first character is alphanumeric, get ready to push to stack.
while (expression[i] != ' ') { //Wait until hitting space to ensure entire number is pushed, not just 1 digit
numberToPush << expression[i];
i++;
}
S.push(numberToPush);
}
else if (IsOperator(expression[i])) { //When an operator is hit, top two strings are taken from stack and converted to double.
switch (expression[i]) { //Operation is applied, they are converted back to string and result is pushed onto stack
case '+':
leftOpString == S.top().str();
S.pop();
rightOpString == S.top().str();
S.pop();
leftOp = atof(leftOpString.c_str());
rightOp = atof(rightOpString.c_str());
tempResult = leftOp + rightOp;
tempResultString = to_string(tempResult);
for (int i = 0; i < tempResultString.length() - 1; i++) {
tempResultSS << tempResultString.at(i);
}
S.push(tempResultSS);
break;
case '-':
leftOpString == S.top().str();
S.pop();
rightOpString == S.top().str();
S.pop();
leftOp = atof(leftOpString.c_str());
rightOp = atof(rightOpString.c_str());
tempResult = leftOp - rightOp;
tempResultString = to_string(tempResult);
for (int i = 0; i < tempResultString.length() - 1; i++) {
tempResultSS << tempResultString.at(i);
}
S.push(tempResultSS);
break;
case '*':
leftOpString == S.top().str();
S.pop();
rightOpString == S.top().str();
S.pop();
leftOp = atof(leftOpString.c_str());
rightOp = atof(rightOpString.c_str());
tempResult = leftOp * rightOp;
tempResultString = to_string(tempResult);
for (int i = 0; i < tempResultString.length() - 1; i++) {
tempResultSS << tempResultString.at(i);
}
S.push(tempResultSS);
break;
case '/':
leftOpString == S.top().str();
S.pop();
rightOpString == S.top().str();
S.pop();
leftOp = atof(leftOpString.c_str());
rightOp = atof(rightOpString.c_str());
tempResult = leftOp/rightOp;
tempResultString = to_string(tempResult);
for (int i = 0; i < tempResultString.length() - 1; i++) {
tempResultSS << tempResultString.at(i);
}
S.push(tempResultSS);
break;
case '^':
leftOpString == S.top().str();
S.pop();
rightOpString == S.top().str();
S.pop();
leftOp = atof(leftOpString.c_str());
rightOp = atof(rightOpString.c_str());
tempResult = pow(leftOp, rightOp);
tempResultString = to_string(tempResult);
for (int i = 0; i < tempResultString.length() - 1; i++) {
tempResultSS << tempResultString.at(i);
}
S.push(tempResultSS);
break;
}
}
}
finalResultString == S.top().str();
return finalResultString;
}
下面是完整的错误信息:
Error C2280 'std::basic_stringstream<char,std::char_traits<char>,std::allocator<char>>::basic_stringstream(const std::basic_stringstream<char,std::char_traits<char>,std::allocator<char>> &)': attempting to reference a deleted function ConsoleApplication2 c:\program files (x86)\microsoft visual studio 14.0\vc\include\xmemory0 737
这里是线733-738,其中包含在那里说的错误在于行:
template<class _Objty,
class... _Types>
void construct(_Objty *_Ptr, _Types&&... _Args)
{ // construct _Objty(_Types...) at _Ptr
::new ((void *)_Ptr) _Objty(_STD forward<_Types>(_Args)...);
}
我将不胜感激,如果任何人都可以在正确的方向towar点我ds解决这个问题。
*您的*代码中的哪一行停止了?查看调用堆栈并查看程序的哪一行最终调用此函数。 – PaulMcKenzie
@PaulMcKenzie这不是编译器错误吗? – Barmar
但是,某些时候的错误消息将显示最终调用该函数的代码行。 – PaulMcKenzie