2017-04-10 1631 views
0

我正在研究C++项目,其中一个功能是采用中缀表示法中的代数表达式,将其转换为修补后符号并解决该问题。转换到后期修复工作正常,我相信我的代码用于评估后修复表达式将按预期工作,但由于错误C2280,我无法编译。下面是定位后评估的代码(我很新的C++,因此任何人与它经历,当他们看到有多穷,这可能是可以有一个动脉瘤):C++错误C2280:尝试引用已删除的函数

string EvaluatePostfix(string expression) { 
    double num; 
    double leftOp; 
    double rightOp; 
    string leftOpString; 
    string rightOpString; 
    stringstream numberToPush; 
    double tempResult; 
    string tempResultString; 
    stringstream tempResultSS; 
    stack<stringstream> S; 
    string finalResultString; 


    for (std::size_t i = 0, l = expression.size(); i < l; ++i) { 
     if (expression[i] == '=') 
      break; 
     else if (isalnum(expression[i])) { //If the first character is alphanumeric, get ready to push to stack. 
      while (expression[i] != ' ') { //Wait until hitting space to ensure entire number is pushed, not just 1 digit 
       numberToPush << expression[i]; 
       i++; 
      } 
      S.push(numberToPush); 

     } 

     else if (IsOperator(expression[i])) { //When an operator is hit, top two strings are taken from stack and converted to double. 
      switch (expression[i]) {   //Operation is applied, they are converted back to string and result is pushed onto stack 
      case '+': 
       leftOpString == S.top().str(); 
       S.pop(); 
       rightOpString == S.top().str(); 
       S.pop(); 
       leftOp = atof(leftOpString.c_str()); 
       rightOp = atof(rightOpString.c_str()); 
       tempResult = leftOp + rightOp; 
       tempResultString = to_string(tempResult); 
       for (int i = 0; i < tempResultString.length() - 1; i++) { 
        tempResultSS << tempResultString.at(i); 
       } 
       S.push(tempResultSS); 
       break; 
      case '-': 
       leftOpString == S.top().str(); 
       S.pop(); 
       rightOpString == S.top().str(); 
       S.pop(); 
       leftOp = atof(leftOpString.c_str()); 
       rightOp = atof(rightOpString.c_str()); 
       tempResult = leftOp - rightOp; 
       tempResultString = to_string(tempResult); 
       for (int i = 0; i < tempResultString.length() - 1; i++) { 
        tempResultSS << tempResultString.at(i); 
       } 
       S.push(tempResultSS); 
       break; 
      case '*': 
       leftOpString == S.top().str(); 
       S.pop(); 
       rightOpString == S.top().str(); 
       S.pop(); 
       leftOp = atof(leftOpString.c_str()); 
       rightOp = atof(rightOpString.c_str()); 
       tempResult = leftOp * rightOp; 
       tempResultString = to_string(tempResult); 
       for (int i = 0; i < tempResultString.length() - 1; i++) { 
        tempResultSS << tempResultString.at(i); 
       } 
       S.push(tempResultSS); 
       break; 
      case '/': 
       leftOpString == S.top().str(); 
       S.pop(); 
       rightOpString == S.top().str(); 
       S.pop(); 
       leftOp = atof(leftOpString.c_str()); 
       rightOp = atof(rightOpString.c_str()); 
       tempResult = leftOp/rightOp; 
       tempResultString = to_string(tempResult); 
       for (int i = 0; i < tempResultString.length() - 1; i++) { 
        tempResultSS << tempResultString.at(i); 
       } 
       S.push(tempResultSS); 
       break; 
      case '^': 
       leftOpString == S.top().str(); 
       S.pop(); 
       rightOpString == S.top().str(); 
       S.pop(); 
       leftOp = atof(leftOpString.c_str()); 
       rightOp = atof(rightOpString.c_str()); 
       tempResult = pow(leftOp, rightOp); 
       tempResultString = to_string(tempResult); 
       for (int i = 0; i < tempResultString.length() - 1; i++) { 
        tempResultSS << tempResultString.at(i); 
       } 
       S.push(tempResultSS); 
       break; 
      } 
     } 
    } 
    finalResultString == S.top().str(); 
    return finalResultString; 

} 

下面是完整的错误信息:

Error C2280 'std::basic_stringstream<char,std::char_traits<char>,std::allocator<char>>::basic_stringstream(const std::basic_stringstream<char,std::char_traits<char>,std::allocator<char>> &)': attempting to reference a deleted function ConsoleApplication2 c:\program files (x86)\microsoft visual studio 14.0\vc\include\xmemory0 737 

这里是线733-738,其中包含在那里说的错误在于行:

template<class _Objty, 
    class... _Types> 
    void construct(_Objty *_Ptr, _Types&&... _Args) 
    { // construct _Objty(_Types...) at _Ptr 
    ::new ((void *)_Ptr) _Objty(_STD forward<_Types>(_Args)...); 
    } 

我将不胜感激,如果任何人都可以在正确的方向towar点我ds解决这个问题。

+2

*您的*代码中的哪一行停止了?查看调用堆栈并查看程序的哪一行最终调用此函数。 – PaulMcKenzie

+1

@PaulMcKenzie这不是编译器错误吗? – Barmar

+1

但是,某些时候的错误消息将显示最终调用该函数的代码行。 – PaulMcKenzie

回答

1

据巴曼制成,回答HairyDuck给出,按照stringstream的参考注释

http://www.cplusplus.com/reference/sstream/stringstream/stringstream/

其中该复制操作状态被删除 拷贝(3)
字符串流(常量字符串流&) =删除;

并假设堆栈的std ::堆栈它指定推

“在堆栈的顶部插入新的元件,其电流顶部元件上面。此新元素的内容被初始化为的副本VAL“。 http://www.cplusplus.com/reference/stack/stack/push/

=>请勿使用不可复制类型的堆栈:: push。

相关问题