2012-07-09 128 views
0

我正在开发一个需要数据库交互性的wordpress插件。我正在使用我的激活挂钩中的dbDelta函数向数据库添加多个表。 dbDelta函数上周工作时为,但是当我去添加另一个表格时,没有发生任何事情。我无法添加列或更改现有表的属性。有人建议在运行dbDelta之前分解sql命令,但这也不起作用。wordpress的dbDelta函数停止工作

之前你问:是的,我已经阅读了codex页面,并按照格式化说明。

下面是代码:

<?php 
function install() 
{ 

    global $wpdb; //use the global variable wpdb, a class used to interact with wordpress's database 

    //define table names, using the the db's prefix 
    $gist_table = $wpdb->prefix . "cookbook_gist"; 
    $tag_table = $wpdb->prefix . "cookbook_tags"; 
    $tagKey_table = $wpdb->prefix . "cookbook_tagKeys"; 
    $comment_table = $wpdb->prefix . "cookbook_comments"; 
    $blacklist_table = $wpdb->prefix . "cookbook_blacklist"; 

    //Include the wpdb function 

    require_once(ABSPATH . 'wp-admin/includes/upgrade.php'); //the dbDelta function is in this file 

    //create the sql statements to add the tables 

    $sql = "CREATE TABLE $gist_table (
    gist_id mediumint NOT NULL, 
    last_cached datetime DEFAULT '0000-00-00 00:00:00' NOT NULL, 
    last_updated datetime DEFAULT '0000-00-00 00:00:00' NOT NULL, 
    author tinytext NOT NULL, 
    description mediumtext NOT NULL, 
    header mediumtext NOT NULL, 
    body text NOT NULL, 
    footer mediumtext NOT NULL, 
    PRIMARY KEY (gist_id) 
    );"; 

    //Actually add the table 
    dbDelta($sql); 

    $sql = "CREATE TABLE $tag_table (
    tag_id mediumint NOT NULL AUTO_INCREMENT, 
    tag tinytext NOT NULL, 
    PRIMARY KEY (tag_id) 
    );"; 

    dbDelta($sql); 

    $sql ="CREATE TABLE $tagKey_table (
    id mediumint NOT NULL AUTO_INCREMENT, 
    gist_id mediumint NOT NULL, 
    tag_id mediumint NOT NULL, 
    PRIMARY KEY (id) 
    );"; 

    dbDelta($sql); 

    $sql = "CREATE TABLE $comment_table (
    id mediumint NOT NULL, 
    gist_id mediumint NOT NULL, 
    author tinytext NOT NULL, 
    date_created datetime NOT NULL, 
    comment mediumtext NOT NULL, 
    newcol text NOT NULL, 
    PRIMARY KEY (id) 
    );"; 

    dbDelta($sql); 


    $sql = "CREATE TABLE $blacklist_table (
    gist_id mediumint NOT NULL, 
    PRIMARY KEY (gist_id) 
    );"; 


    dbDelta($sql); //makes the changes to the wp database  
} 

?> 

回答

0

很抱歉的混乱。几天前我的托管服务改变了我们托管的服务器;我仍然登录到旧的服务器来管理数据库。当我登录到正确的服务器时,更改已按预期进行。