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我正在创建一个预订应用程序。我正在使用UIPickers显示打开的时间。我有选择器功能齐全,但不知道如何在用户从提供的选项中选择一个后删除预订时间。我对Xcode比较陌生,所以任何信息都非常感谢!从选择中删除字符串从UIPicker
import Foundation
import UIKit
import Firebase
import FirebaseDatabase
class sTimeSelectionViewController:UIViewController,UIPickerViewDataSource,UIPickerViewDelegate {
@IBOutlet weak var myPicker: UIPickerView!
@IBOutlet weak var myLabel: UILabel!
let pickerData = ["9:30","10:30","11:30","12:30","1:30","2:30"]
override func viewDidLoad() {
super.viewDidLoad()
myPicker.dataSource = self
myPicker.delegate = self
myPicker.tag = 1
}
func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int {
return 1
}
func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
return pickerData.count
}
func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
return pickerData[row]
}
func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {
myLabel.text = pickerData[row]
}
@IBAction func postData(sender: AnyObject) {
let ref = FIRDatabase.database().referenceFromURL("deleted URL")
ref.child("Time").setValue(myLabel.text)
}
}
谢谢!
嗨,狮子座。感谢您的代码!我有一个问题。我已经将您的代码添加到我的项目中,并且在按下按钮选择该行之前数据正在删除自己(当您滚动数据时,数据会自动删除)。任何想法如何可以修复? –