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嗨,我加入,和组使用此MySQL的代码生成下面这样的数据:MySQL的左由
代码:
SELECT L.LEAVETYPE, LA.IDLEAVETYPE, LA.IDLEAVETABLE, SUM(LA.NOOFDAYS)
FROM LEAVETYPE AS L
LEFT JOIN LEAVEAPPLICATION AS LA ON LA.IDLEAVETYPE = L.IDLEAVETYPETABLE
GROUP BY L.LEAVETYPE
当我将WHERE条件那只能说明具有值的LeaveType。我如何显示包括null在内的所有leavetype(像在第一张图片中)?
SELECT L.LEAVETYPE, LA.IDLEAVETYPE, LA.IDLEAVETABLE, SUM(LA.NOOFDAYS)
FROM LEAVETYPE AS L
LEFT JOIN LEAVEAPPLICATION AS LA ON LA.IDLEAVETYPE = L.IDLEAVETYPETABLE
WHERE LA.IDSTAFFTABLE='24'
GROUP BY L.LEAVETYPE
+1:由24秒打我 – 2010-09-27 02:24:25
感谢它的作品! – cyberfly 2010-09-27 03:11:45