结合多个MySQL查询到一个

IM学习的MySQL命令，并结合多个查询的方法，所以为了获得这个目标，现在我需要把这些查询组合：结合多个MySQL查询到一个

list($TotalVisitsToday) = $db->sql_fetchrow($db->sql_query("SELECT COUNT(DISTINCT ip_address) FROM table_iptracking WHERE `date_time` between '$yesterday' and '$today' ")); 
    list($TotalVisitsYesterday) = $db->sql_fetchrow($db->sql_query("SELECT COUNT(DISTINCT ip_address) FROM table_iptracking WHERE `date_time` between '$yesterday_1' and '$yesterday' ")); 

    list($TotalPVisitsToday) = $db->sql_fetchrow($db->sql_query("SELECT count(ipid) FROM table_iptracking WHERE `date_time` between '$yesterday' and '$today'")); 
    list($TotalPVisitsYesterday) = $db->sql_fetchrow($db->sql_query("SELECT count(ipid) FROM table_iptracking WHERE `date_time` between '$yesterday_1' and '$yesterday'")); 

    list($TotalCrawlers) = $db->sql_fetchrow($db->sql_query("SELECT count(ipid) FROM table_iptracking WHERE hostname LIKE '%crawl%' "));

我对如何不知道混合上面的行！

来源

2010-10-03 Mac Taylor

你可能形成的SQL语句组成工会，像...

SELECT COUNT(DISTINCT ip_address) 
    FROM table_iptracking 
    WHERE `date_time` between '$yesterday' and '$today' 
UNION 
SELECT COUNT(DISTINCT ip_address) 
    FROM table_iptracking 
    WHERE `date_time` between '$yesterday_1' and '$yesterday' 
UNION 
SELECT count(ipid) 
    FROM table_iptracking 
    WHERE `date_time` between '$yesterday' and '$today' 
UNION 
SELECT count(ipid) 
    FROM table_iptracking 
    WHERE `date_time` between '$yesterday_1' and '$yesterday' 
UNION 
SELECT count(ipid) 
    FROM table_iptracking 
    WHERE hostname LIKE '%crawl%'

我不能说我会建议这一点，虽然。结果集不同行意味着不同的东西，从长远来看可能会证明麻烦。

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2010-10-03 09:16:27

我试过联盟之前，你建议这个答案，但结果是零和不起作用 – 2010-10-05 18:19:56

我不知道你的最终目标，但如果你只是想在一个查询，你可以做这样的：

SELECT 
(SELECT COUNT(DISTINCT ip_address) FROM table_iptracking WHERE 'date_time' between '$yesterday' and '$today') COUNT1, 
(SELECT COUNT(DISTINCT ip_address) FROM table_iptracking WHERE 'date_time' between '$yesterday_1' and  '$yesterday') COUNT2, 
(SELECT COUNT(ipid) FROM table_iptracking WHERE 'date_time' between '$yesterday' and '$today') COUNT3, 
(SELECT COUNT(ipid) FROM table_iptracking WHERE 'date_time' between '$yesterday_1' and '$yesterday') COUNT4, 
(SELECT COUNT(ipid) FROM table_iptracking WHERE hostname LIKE '%crawl%') COUNT5

（你可以在MySQL省略FROM caluse）

来源

2010-10-03 09:26:33

你的答案很酷，我试过了，但它没有工作，你确定的语法吗？ – 2010-10-05 18:19:18

是的，语法是正确的，你会得到什么错误？ – 2010-10-06 02:08:13

另外，它是MySQL还是PHP相关？你确定变量占位符被你的PHP脚本中的值正确替换吗？不幸的是，由于我是一名ASP.NET开发人员，因此我无法帮助您，但语法对MySQL确实有效（实际上很简单）。尝试从MySQL客户端（如MySQL命令行）运行查询以确保其正常工作。 – 2010-10-06 02:24:25

结合多个MySQL查询到一个

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