PHP如果mysqli查询语句

Question

我正在创建一个网站，显示一组问题，但我的问题是检查用户是否回答了问题，如果他们有，显示一个“应答”标签。

但是，目前，即使答案不在提交表中，它也会显示每个问题的“已回答”标签。任何帮助，将不胜感激。

while($data = mysqli_fetch_row($result)){ 
    if($data[0] != null){ 
    echo(' 
    <div class="col-md-4 col-sm-5"> 
    <div class="panel panel-default text-center"> 
     <div class="panel-heading"> 
     <span class="fa-stack fa-5x"> 
      <i class="fa fa-circle fa-stack-2x text-default"></i> 
      <i class="fa fa-codepen fa-stack-1x fa-inverse"></i> 
     </span> 
     </div> 
     <div class="panel-body"> 
     '); 
     if($result4 = mysqli_query($mysqli,"SELECT * FROM submissions where teamID='$teamName' and questionID='$data[0]' and status='correct'")){ 
      echo "Answered"; 
     } else{ 
      echo "Not Answered"; 
     } 

     echo (' 
     <h4>'.$data[6].' - <small><i>'.$data[8].' points</i></small></h4> 
     <p>'.$data[7].'</p> 
     <a href="question.php?id='.$data[0].'" class="btn btn-primary btn-block">View Question </a> 
     </div> 
    </div> 
    </div> 
    ');} else{ 
    echo "No More Questions"; 
    } 
} 

我知道我在这里犯了一个基本或愚蠢的错误，所以任何帮助表示赞赏。

Answer 1

//Mysql query to find number of answers for particular question. 
$answercount = mysqli_query($mysqli, "SELECT * FROM submissions where teamID='$teamName' and questionID='$data[0]' and status='correct'"); 
$answercount = mysqli_num_rows($answercount); 

//PHP code 
if($answercount>0){ 
    echo "Answered"; 
} else{ 
    echo "Not Answered"; 
} 

Answer 2

你忘记mysqli_query("")

if ($result4 = mysqli_query($con, "SELECT * FROM submissions where teamID='$teamName' and questionID='$data[0]' and status='correct'")) { 
    echo "Answered"; 
} else { 
    echo "Not Answered"; 
}