那么,我有一个关于三元运算符逗号的问题。 废话少说,代码如下:在条件三元运算符中使用逗号时发现的东西?
void test_comma_in_condition(void)
{
int ia, ib, ic;
ia = ib = ic = 0;
bool condition=true;
cout<<"Original:"<<endl;
cout<<"ia: "<<ia<<endl;
cout<<"ib: "<<ib<<endl;
condition?(ia=1, ib=2):(ia=11, ib=12);
cout<<"After:"<<endl;
cout<<"ia: "<<ia<<endl;
cout<<"ib: "<<ib<<endl;
ia = ib = ic = 0;
condition?ia=1, ib=2, ic=3:ib=22,ia=21, ic=23;
cout<<"The operation must be bracketed, or you'll see..."<<endl;
cout<<"ia: "<<ia<<endl;
cout<<"ib: "<<ib<<endl;
cout<<"ic: "<<ic<<endl;
condition?ia=1, ib=2, ic=3:ia=21, ib=22, ic=23;
cout<<"The operation must be bracketed, or you'll see..."<<endl;
cout<<"ia: "<<ia<<endl;
cout<<"ib: "<<ib<<endl;
cout<<"ic: "<<ic<<endl;
return;
}
输出将是这样的:
Original:
ia: 0
ib: 0
After:
ia: 1
ib: 2
The operation must be bracketed, or you'll see...
ia: 21
ib: 2
ic: 23
The operation must be bracketed, or you'll see...
ia: 1
ib: 22
ic: 23
这是合法的吗?
你在说'a? b:c,d'应该是'a? b:(c,d)'而不是'(a?b:c),d'。在不了解哪个是正确的问题的情况下,您怀疑编译器的原因是什么? – hvd 2012-02-08 08:02:43
是的,它是合法的 - 但也是不可读的。 – 2012-02-08 08:04:31