转换1-d阵列2-d阵列重叠

Question

我需要的大小为N的一个维数组转换为尺寸A的二维阵列* B> N。让我们采取这样的情况下：

int oneDimensionalArray[6] = {7, 8, 10, 11, 12, 15}; 
//then the second array would be 
int twoDimensionalArray[2][4] = {{7, 8, 10, 11}, 
           {10, 11, 12, 15}}; 

这用于数字声音处理中使用的所谓叠加方法。我曾尝试这种做法赋予不当的结果：

for(unsigned long i = 0; i < amountOfWindows; i++) 
    { 
     for(unsigned long j = hopSize; j < windowLength; j++) 
     { 
      //buffer without the overlapping 
      if((i * amountOfWindows + j) >= bufferLength) 
       break; 

      windowedBuffer[i][j] = unwindowedBuffer[i * amountOfWindows + j]; 
     } 
    } 

    for(unsigned long i = 1; i < amountOfWindows; i++) 
    { 
     for(unsigned long j = 0; j < hopSize; j++) 
     { 
      // Filling the overlapping region 
      windowedBuffer[i][j] = windowedBuffer[i-1][windowLength - hopSize + i]; 
     } 
    } 

我也试着寻找使用模运算的关系，但我不能找到合适的人。这是我试过的一个：

windowedBuffer[m][n % (windowLength - hopSize)] = unwindowedBuffer[n]; 

Answer 1

既然你已经知道了hopSize（从您的评论），你想要的是简单的：

for (size_t i = 0; i < amountOfWindows; ++i) { 
    for (size_t j = 0; j < windowLength; ++j) { 
     windowedBuffer[i][j] = unwindowedBuffer[i * hopSize + j]; 
    } 
} 

凡amountOfWindows，windowLength和hopSize你参数（在你的例子中分别是2,4和2）。