我有包含JSON在我得为对象 但是当我使用laravel模型然后将数据它显然返回JSON或字符串,我必须每一个地方,在那里我用这个模型解码列的表(这是不干燥的概念),但事情是,如果我拉一个记录,一个地方,那么它的代码,并确定只有一个执行,但如果我要拉的数据和多个地方的集合,然后我要运行相同的解码什么每次都是在有任何laravel方式,可以为我做的,而不是使用自制的循环如何使用laravel5将数据mysql中的json数据作为对象?
下面是表
+-----------------------------------------------------------------------------+
| table |
+-----------------------------------------------------------------------------+
|id | title | text |
+-----------------------------------------------------------------------------+
| 1 | A1 | {"subject":"Subject1","word":"Lorem ipsum dolor sit amet, ..."} |
| 2 | A2 | {"subject":"Subject2","word":"Lorem ipsum dolor sit amet, ..."} |
| 3 | A3 | {"subject":"Subject3","word":"Lorem ipsum dolor sit amet, ..."} |
| 4 | A4 | {"subject":"Subject4","word":"Lorem ipsum dolor sit amet, ..."} |
| 5 | A5 | {"subject":"Subject5","word":"Lorem ipsum dolor sit amet, ..."} |
| 6 | A6 | {"subject":"Subject6","word":"Lorem ipsum dolor sit amet, ..."} |
| 7 | A7 | {"subject":"Subject7","word":"Lorem ipsum dolor sit amet, ..."} |
| 8 | A8 | {"subject":"Subject8","word":"Lorem ipsum dolor sit amet, ..."} |
| 9 | A9 | {"subject":"Subject9","word":"Lorem ipsum dolor sit amet, ..."} |
| 10| A10 | {"subject":"Subject10","word":"Lorem ipsum dolor sit amet..."} |
+-----------------------------------------------------------------------------+
我已经尝试了本
$tables = TableModel::all();
foreach ($tables as &$table) {
$table->text = json_decode($table->text);
}
结果就是我想要
Array
(
[0] => stdClass Object
(
[id] => 1
[title] => A1
[text] => stdClass Object
(
[subject] => Subject1
[word] => Lorem ipsum dolor sit amet...
)
)
[1] => stdClass Object
(
[id] => 2
[title] => A2
[text] => stdClass Object
(
[subject] => Subject2
[word] => Lorem ipsum dolor sit amet...
)
)
...
)
如果有什么简单的方法即是更有效,并按照干 然后跟我分享。
在此先感谢。
我叫过它然后循环模式,并使用'json_decode对象覆盖那么,元件()' – User97798