我的程序旨在制作一个名词的复数。错误来自行"char *pstr = userNoun[lengthStr - 1];"
。有人能告诉我我的错误在这里吗?初始化从无整型转换的整数创建指针
#include <string.h>
#include <stdio.h>
#include <stdlib.h>
void pluralNoun(char userNoun[27]){
int lengthStr = 0;
const char caseOne[2] = "es";
const char caseTwo[2] = "s";
lengthStr = strlen(userNoun);
char *pstr = userNoun[lengthStr - 1];
if(strncmp(pstr - 1, "ch", 2) == 0){
strcat(userNoun, caseOne);
}
else if(strncmp(pstr - 1, "sh", 2) == 0){
strcat(userNoun, caseOne);
}
else if(*pstr == 's'){
strcat(userNoun, caseOne);
}
else if(*pstr == 'y'){
userNoun[lengthStr - 1] = 'i';
strcat(userNoun, caseOne);
}
else {
strcat(userNoun, caseTwo);
}
printf("The plural of your noun is %s\n", userNoun);
}
int main(void){
char userVar[25];
printf("Enter a noun no more than 25 characters in length in lower case letters:\n");
scanf("%s", userVar);
pluralNoun(userVar);
return 0;
}
你的意思是:'char * pstr =&userNoun [lengthStr - 1];' – tapananand
'userNoun [lengthStr - 1]'是一个'char'。如果你想要一个指向字符地址的指针,你应该直接执行'&(userNoun [lengthStr - 1])'或用户指针算术。 – Jameson