使用原始表达式Laravel 4

Question

请告诉我该怎么办这一关正确的查询

select @a:=POW(max(count_votes), 1/10) from users; 

select id,name,raiting, count_votes, ((LOG(@a,count_votes))+raiting)/2 as actual_raiting from users order by actual_raiting desc ; 

试过这样

$rating = DB::statement('select @a:=POW(max(count_votes), 1/10) from users; 

select id,name,raiting, count_votes, ((LOG(@a,count_votes))+raiting)/2 as actual_raiting from users order by actual_raiting desc; '); 

return $rating; 

和

$rating = DB::table('users') 
        ->select(DB::raw('*, @a:=POW(max(count_votes), 1/10) ')) 
        ->select(DB::raw('*,raiting, count_votes, ((LOG(@a,count_votes))+raiting)/2 as actual_raiting')) 
        ->orderBy("actual_raiting") 
        ->get(); 

    return $rating; 

我究竟做错了什么？

PS：我的英语水平

Answer 1

尝试把它们都放在一个选择：

$rating = DB::table('users') 
      ->select(DB::raw('*, raiting, count_votes, ((LOG(POW(max(count_votes), 1/10),count_votes))+raiting)/2 as actual_raiting')) 
      ->orderBy("actual_raiting") 
      ->get(); 

Answer 2

/不好意思试试这个：

$rating1 = DB::select(DB::raw('select @a:=POW(max(count_votes), 1/10) from users')); 

$rating2 = DB::select(DB::raw('select id,name,raiting, count_votes, ((LOG(@a,count_votes))+raiting)/2 as actual_raiting from users order by actual_raiting desc; ')); 

echo "<pre>"; 
print_r($rating1); 
print_r($rating2); 
echo "</pre>"; 
exit; 

看，如果没有什么帮助。