阿贾克斯成功性反应

Question

我有下面的代码是工作的罚款：如果我的2“如果”一个“其他”的声明（见下文）之间把

success: function (upd_rsp){ 
    //if email is not register 
    if(upd_rsp == "email_no"){ 
    exstInfo.text("This E-mail is not registered in our Database!"); 
    exstInfo.addClass("error"); 
    return false; 
    } 

    //if email & pass don't match 
    if(upd_rsp == "email_pass_no"){ 
    matchInfo.text("Email and Password don't match!"); 
    matchInfo.addClass("error"); 
    return false; 
    } 

现在，第二个“如果”没有得到执行。我错在哪里？

else{ 
    exstInfo.text(""); 
    exstInfo.removeClass("error"); 
    return true; 
    } 

解决方案工作得很好。

Answer 1

如果在执行第二个if之前设置了return值，则脚本将在发送return后停止。

这是许多方法可以做到这一个：

success: function (upd_rsp){ 
    //if email is not register 
    var email_error = false; 
    var pass_error = false; 
    if(upd_rsp == "email_no"){ 
    exstInfo.text("This E-mail is not registered in our Database!"); 
    exstInfo.addClass("error"); 
    email_error = true; 
    } else { 
    exstInfo.text(""); 
    exstInfo.removeClass("error"); 
    email_error = false; 
    } 


    //if email & pass don't match 
    if(upd_rsp == "email_pass_no"){ 
    matchInfo.text("Email and Password don't match!"); 
    matchInfo.addClass("error"); 
    pass_error = true; 
    } else { 
    .... 
    pass_error = false; 
    } 

    if(email_error == true || pass_error == true){ 
    return false; 
    } else { 
    return true; 
    }