与部分视图和LogOn中的模型冲突

Question

传递到字典中的模型项目类型为'System.Collections.Generic.List`1 [PM.Models.Product]'，但是此字典需要类型为' PM.Models.LogOnModel”。

问题：

Ошибка сервера в приложении '/'. 
The model item passed into the dictionary is of type 'System.Collections.Generic.List`1[PM.Models.Product]', but this dictionary requires a model item of type 'PM.Models.LogOnModel'. 
Описание: Необработанное исключение при выполнении текущего веб-запроса. Изучите трассировку стека для получения дополнительных сведений о данной ошибке и о вызвавшем ее фрагменте кода. 

Сведения об исключении: System.InvalidOperationException: The model item passed into the dictionary is of type 'System.Collections.Generic.List`1[PM.Models.Product]', but this dictionary requires a model item of type 'PM.Models.LogOnModel'. 

Ошибка источника: 

Строка 1: @using PM.Models 
Строка 2: @{PM.Models.LogOnModel LOM=new LogOnModel();} 
Строка 3: @RenderPage("../Account/LogOn.cshtml"); 

我尝试使用一个PartialView在主页来查看用户字段登录名和密码登录，在Site.And对存在的另一种局部视图的用户列表产品在现场。 但我有问题，请帮助我。

这例子我登录页的

@model PM.Models.LogOnModel 
@{ 
    ViewBag.Title = "Log On"; 
} 
<script src="@Url.Content("~/Scripts/jquery.validate.min.js")" type="text/javascript"></script> 
<script src="@Url.Content("~/Scripts/jquery.validate.unobtrusive.min.js")" type="text/javascript"></script> 
<script type="text/javascript" language="javascript"> 
    var UserNameTextBox = document.getElementById("login"); 
    UserNameTextBox.textContent = UserNameTextBox.textContent + "123"; 
</script> 


<link href="../../Content/themes/our/Style.css" rel="stylesheet" type="text/css" /> 

@using (Html.BeginForm("LogOn", "Account")) 
{  
    <div id="login" > 
    @Html.TextBoxFor(m => m.UserName, new { @class = "inputLogin" }) 
    @Html.PasswordFor(m => m.Password, new { @class = "inputLogin" }) 
    @Html.CheckBoxFor(m => m.RememberMe) 
    @Html.LabelFor(m => m.RememberMe, new { @class = "rememberText" }) 
    <div id="ErrorMessage"> 
    @Html.ValidationSummary(true, "Авторизоваться не удалось, проверьте введенные данные.") 
    </div> 

    <div id="loginButtons"> 
      @Html.ActionLink(" ", "Register", "Account", routeValues: null, htmlAttributes: new { id = "registerLink", @class = "register" }) 
      <input type="submit" value="Войти" id="loginButton" title="Войти" /> 
     </div> 
    <div id="loginWith"> 
     Войти через: &nbsp;&nbsp;&nbsp; 
     <a href="" style="text-decoration:none;"><img alt="" class="SocialIcon" src="../../Content/img/VKicon.PNG" />&nbsp;&nbsp;&nbsp;&nbsp;</a> 
     <a href="" style="text-decoration:none"><img alt="" class="SocialIcon" src="../../Content/img/FBIcon.PNG" />&nbsp;&nbsp;&nbsp;</a> 
     <a href="" style="text-decoration:none"><img alt="" class="SocialIcon" src="../../Content/img/TwitterIcon.PNG" /></a> 
    </div> 
    </div> 

} 

这个例子所需的另一种模式我的搜索页的该登录

@model IEnumerable<PM.Models.Product> 

<p> 
    @Html.ActionLink("Create New", "Create") 
</p> 
<table> 
    <tr> 
     <th> 
      @Html.DisplayNameFor(model => model.Name) 
     </th> 
     <th> 
      @Html.DisplayNameFor(model => model.Description) 
     </th> 
     <th> 
      @Html.DisplayNameFor(model => model.Type) 
     </th> 
     <th> 
      @Html.DisplayNameFor(model => model.Image) 
     </th> 
     <th> 
      @Html.DisplayNameFor(model => model.Partition) 
     </th> 
     <th></th> 
    </tr> 

@foreach (var item in Model) { 
    <tr> 
     <td> 
      @Html.DisplayFor(modelItem => item.Name) 
     </td> 
     <td> 
      @Html.DisplayFor(modelItem => item.Description) 
     </td> 
     <td> 
      @Html.DisplayFor(modelItem => item.Type) 
     </td> 
     <td> 
      @Html.DisplayFor(modelItem => item.Image) 
     </td> 
     <td> 
      @Html.DisplayFor(modelItem => item.Partition) 
     </td> 
     <td> 
      @Html.ActionLink("Edit", "Edit", new { id=item.Id }) | 
      @Html.ActionLink("Details", "Details", new { id=item.Id }) | 
      @Html.ActionLink("Delete", "Delete", new { id=item.Id }) 
     </td> 
    </tr> 
} 

</table> 

帐户电脑板

[AllowAnonymous] 
     public ActionResult LogOn() 
     { 
      string actionName = ControllerContext.RouteData.GetRequiredString("action"); 
      ViewBag.FormAction = actionName; 
      return View(); 
     } 


     // 
     // POST: /Account/LogOn 

     [AllowAnonymous] 
     [HttpPost] 
     public ActionResult LogOn(LogOnModel model, string returnUrl) 
     { 
      if (ModelState.IsValid) 
      { 
       if (System.Web.Security.Membership.ValidateUser(model.UserName, model.Password)) 
       { 
        FormsAuthentication.SetAuthCookie(model.UserName, model.RememberMe); 
        if (Url.IsLocalUrl(returnUrl)) 
        { 
         return Redirect(returnUrl); 
        } 
        else 
        { 
         if (Request.UrlReferrer != null) 
          return Redirect(Request.UrlReferrer.AbsoluteUri); 
         else 
         { 
          return RedirectToAction("Index","Home"); 
         } 
        } 
       } 
       else 
       { 
        ModelState.AddModelError("", "The user name or password provided is incorrect."); 
       } 
      } 

      // If we got this far, something failed, redisplay form 
      return RedirectToAction("Index", "Home", new { login = "incorrect" }); 
     } 

控制器，它工作with Search View

[HttpGet] 
    public ActionResult Search(string KeyWord) 
    { 
     DataManager dm = new DataManager(); 
     List<Product> sended = dm.FindProducts(KeyWord); 
     return View(sended); 
    } 

Answer 1

因此，您有2个部分视图LogOn.cshtml和Search.cshtml分别强烈键入LogOnModel和IEnumerable<Product>。这意味着在渲染这些部分时需要传递正确的模型类型。例如，如果只使用Html.Partial("somePartial")而不指定模型作为第二个参数，则会传递父模型。如果你想指定一个模型，你可以做到以下几点：

@{ 
    var logonModel = new LogOnModel(); 
} 
@Html.Partial("~/Views/Account/LogOn.cshtml", logonModel) 

，或者您可以使用Html.Action帮手，而不是直接包括局部视图，它允许你调用一个控制器动作，将返回部分。但是没有单独的HTTP请求从客户端发送。在相同的请求所有情况：

@Html.Action("LogOn", "Account") 

，现在你的登录方法将被调用，并且必须通过正确的模型：

public ActionResult LogOn() 
{ 
    var model = new LogOnModel(); 
    return PartialView(model); 
} 

[HttpPost] 
public ActionResult LogOn(LogOnModel model, string returnUrl) 
{ 
    ... 
} 

同样代表着搜索部分属实：

@Html.Action("Search", "SomeControllerContainingTheSearchAction")