如何使用AngularJS从PHP文件中提取数据

好吧，我的php文件有问题。我使用AngularJS从php文件中提取一些数据，这里是我的角码。它是W3schools的源代码。但我有一些麻烦大码，如许：如何使用AngularJS从PHP文件中提取数据

<!DOCTYPE html> 
<html> 
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.4.8/angular.min.js"></script> 
<body> 

<div ng-app="myApp" ng-controller="customersCtrl"> 

<ul> 
    <li ng-repeat="x in myData"> 
    {{ x.Name + ', ' + x.Country }} 
    </li> 
</ul> 

</div> 

<script> 
var app = angular.module('myApp', []); 
app.controller('customersCtrl', function($scope, $http) { 
    $http.get("customers.php").then(function (response) { 
     $scope.myData = response.data.records; 
    }); 
}); 
</script> 

</body> 
</html>

所以，我的问题是如何将我格式化PHP读取此

{ 
    "records": [ 
    { 
     "Name": "Alfreds Futterkiste", 
     "City": "Berlin", 
     "Country": "Germany" 
    }, 
    { 
     "Name": "Ana Trujillo Emparedados y helados", 
     "City": "México D.F.", 
     "Country": "Mexico" 
    }, 
    { 
     "Name": "Antonio Moreno Taquería", 
     "City": "México D.F.", 
     "Country": "Mexico" 
    }, 
    { 
     "Name": "Around the Horn", 
     "City": "London", 
     "Country": "UK" 
    }, 
    { 
     "Name": "B's Beverages", 
     "City": "London", 
     "Country": "UK" 
    }, 
    { 
     "Name": "Berglunds snabbköp", 
     "City": "Luleå", 
     "Country": "Sweden" 
    }, 
    { 
     "Name": "Blauer See Delikatessen", 
     "City": "Mannheim", 
     "Country": "Germany" 
    }, 
    { 
     "Name": "Blondel père et fils", 
     "City": "Strasbourg", 
     "Country": "France" 
    }, 
    { 
     "Name": "Bólido Comidas preparadas", 
     "City": "Madrid", 
     "Country": "Spain" 
    }, 
    { 
     "Name": "Bon app'", 
     "City": "Marseille", 
     "Country": "France" 
    }, 
    { 
     "Name": "Bottom-Dollar Marketse", 
     "City": "Tsawassen", 
     "Country": "Canada" 
    }, 
    { 
     "Name": "Cactus Comidas para llevar", 
     "City": "Buenos Aires", 
     "Country": "Argentina" 
    }, 
    { 
     "Name": "Centro comercial Moctezuma", 
     "City": "México D.F.", 
     "Country": "Mexico" 
    }, 
    { 
     "Name": "Chop-suey Chinese", 
     "City": "Bern", 
     "Country": "Switzerland" 
    }, 
    { 
     "Name": "Comércio Mineiro", 
     "City": "São Paulo", 
     "Country": "Brazil" 
    } 
    ] 
}

这一切都形成W3schools.com我” m试图重现一个家庭作业的PHP文件，但可以弄清楚如何格式化PHP来阅读这个。请帮忙。此外，这里是w3school示例的链接，我使用https://www.w3schools.com/angular/angular_http.asp它在JSON示例下。这个例子很好，但它只是帮助角部分而不是PHP部分，我无法找到任何信息。

感谢

来源

2017-04-12 Mason White

你甚至不明白'$ http.get'是干什么的？如果没有读到 – Augwa

我遇到的问题是使用$ http.get获取数据。根据我的理解，它与ajax请求类似。我在后台出现问题 –

那么到目前为止，您对PHP的处理方式有哪些？ – Augwa

把它放在你的文件的PHP

$conn = new mysqli('localhost','root','','project'); 
$sql="SELECT * FROM ..."; 
$result = mysqli_query($conn,$sql); 

$rows = array(); 
if($result){ 
while($r = mysqli_fetch_assoc($result)) { 
    $rows[] = $r; 
} 
print '{"records":' .json_encode($rows) ."}"; 
}else{ 
    echo mysqli_error(); 
}

来源

2017-04-12 04:27:24 Akashii

试试这个：

 <?php 
     $dbhost = 'HOSTNAME'; 
     $dbuser = 'DBUSERNAME'; 
     $dbpass = 'DBPASSWORD'; 
     $dbname = 'DATABASENAME'; 
     $conn = mysqli_connect($dbhost, $dbuser, $dbpass,$dbname); 

     if(! $conn) { 
      die('Could not connect: ' . mysqli_error()); 
     } 
     $sql = 'SELECT * FROM tbl_name'; 
     $result = mysqli_query($conn, $sql); 

     if (mysqli_num_rows($result) > 0) { 
      while($row = mysqli_fetch_assoc($result)) { 
       $rows[] = $row; 
      } 
      print "{'records':" .json_encode($rows) ."}"; 
     } else { 
      echo "0 results"; 
     } 
     mysqli_close($conn); 
     ?>

来源

2017-04-12 07:26:19

如何使用AngularJS从PHP文件中提取数据

回答

相关问题