与日期相比较？

Question

使用SQL Server 2000

表1

ID Name, Date, TimeIn, TimeOut, DateIn, Dateout 

AEAA00294 Alexander 13/10/2008 09:00:00 18:00:00 13/10/2008 13/10/2008 
AEAA00294 Alexander 14/10/2008 16:00:00 02:00:00 14/10/2008 15/10/2008 
AEAA00294 Alexander 16/10/2008 09:00:00 18:00:00 16/10/2008 16/10/2008 

...等，

表2

ID Date 

DATE, TIME, ID 

20081013 103417 AEAA00294 
20081013 151552 AEAA00294 
20081013 170836 AEAA00294 
20081013 170909 AEAA00294 
20081013 171015 AEAA00294 
20081014 163648 AEAA00294 
20081014 030838 AEAA00294 
20081015 144708 AEAA00294 
20081015 151133 AEAA00294 
20081016 095211 AEAA00294 

...等，

从以上两个表我正银泰时间是分（时间）银泰在日期和最大（时间）作为从table2的同一日期的Outtime，其中table1.personid = table2.personid。

In table1 DateIn and Dateout Date is same, it should take min (time) and Max (time) on the same date from the table2 

Suppose table1 DateIn and Dateout Date is different, it should take min (time) and Max (time) from table2 compare with table1.dateIn and table2.Dateout 

期望输出

ID Date Intime Outtime 

AEAA00294 20081013 103417 171015 
AEAA00294 20081014 030838 151133 

...等，

我的查询

SELECT DISTINCT DERIVEDTBL.PERSONID, DERIVEDTBL.CARDEVENTDATE, MIN(DERIVEDTBL.CARDEVENTTIME) AS INTIME, MAX(DERIVEDTBL.CARDEVENTTIME) AS OUTTIME, tmp_Cardevent1.Normal_Intime, tmp_Cardevent1.Normal_Outtime, tmp_Cardevent1.CardEventDate AS Expr1, tmp_Cardevent1.DateIn, tmp_Cardevent1.DateOut FROM (SELECT  T_PERSON.PERSONID, T_CARDEVENT.CARDEVENTDATE, CONVERT(VARCHAR(10), SUBSTRING(T_CARDEVENT.CARDEVENTTIME, 1, 2) + ':' + SUBSTRING(T_CARDEVENT.CARDEVENTTIME, 3, 2) + ':' + SUBSTRING(T_CARDEVENT.CARDEVENTTIME, 5, 2), 8) AS CARDEVENTTIME 
FROM T_CARDEVENT LEFT JOIN T_PERSON ON T_CARDEVENT.PERSONID = T_PERSON.PERSONID) DERIVEDTBL INNER JOIN tmp_Cardevent1 ON DERIVEDTBL.PERSONID = tmp_Cardevent1.PERSONID AND DERIVEDTBL.CARDEVENTDATE = tmp_Cardevent1.CardEventDate GROUP BY DERIVEDTBL.CARDEVENTDATE, DERIVEDTBL.PERSONID, tmp_Cardevent1.Normal_Intime, tmp_Cardevent1.Normal_Outtime, tmp_Cardevent1.CardEventDate, tmp_Cardevent1.DateIn, tmp_Cardevent1.DateOut 

表1为我的查询tmp_cardevent1和表2为Derivedtbl。

从上面我想比较derivedtbl日期与tmp_cardevent1 dateIn和DateOut值。

需要查询帮助。

如何查询这种情况？

Answer 1

尝试是这样的

DECLARE @Table1 TABLE(
     ID VARCHAR(50), 
     PNAME VARCHAR(50), 
     Date DATETIME, 
     TimeIN VARCHAR(10), 
     [TimeOut] VARCHAR(10), 
     DateIn DATETIME, 
     DateOut DATETIME 
) 

INSERT INTO @Table1 (ID,PNAME,Date,TimeIN,[TimeOut],DateIn,DateOut) 
SELECT 'AEAA00294','Alexander','13 Oct 2008', '09:00:00', '18:00:00','13 Oct 2008','13 Oct 2008' 
INSERT INTO @Table1 (ID,PNAME,Date,TimeIN,[TimeOut],DateIn,DateOut) 
SELECT 'AEAA00294','Alexander','14 Oct 2008', '16:00:00', '02:00:00','14 Oct 2008','15 Oct 2008' 
INSERT INTO @Table1 (ID,PNAME,Date,TimeIN,[TimeOut],DateIn,DateOut) 
SELECT 'AEAA00294','Alexander','16 Oct 2008', '09:00:00', '18:00:00','16 Oct 2008','16 Oct 2008' 

DECLARE @Table2 TABLE(
     Date DATETIME, 
     [Time] VARCHAR(10), 
     ID VARCHAR(50) 
) 

INSERT INTO @Table2 (Date,[Time],ID) SELECT '13 Oct 2008', '10:34:17', 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '13 Oct 2008' , '15:15:52' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '13 Oct 2008' , '17:08:36' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '13 Oct 2008' , '17:09:09' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '13 Oct 2008' , '17:10:15' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '14 Oct 2008' , '16:36:48' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '14 Oct 2008' , '03:08:38' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '15 Oct 2008' , '14:47:08' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '15 Oct 2008' , '15:11:33' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '16 Oct 2008' , '09:52:11' , 'AEAA00294' 


SELECT t1.ID, 
     t1.PNAME, 
     t1.DateIn, 
     t1.DateOut, 
     MIN(CAST(t2In.[Time] AS DATETIME)), 
     MAX(CAST(t2Out.[Time] AS DATETIME)) 
FROM @Table1 t1 LEFT JOIN 
     @Table2 t2IN ON t1.ID = t2IN.ID 
         AND t1.DateIn = t2IN.Date LEFT JOIN 
     @Table2 t2Out ON t1.ID = t2Out.ID 
         AND t1.DateOut = t2Out.Date 
GROUP BY t1.ID, 
     t1.PNAME, 
     t1.DateIn, 
     t1.DateOut 

Answer 2

我想这会做到这一点：

update table1 set timein=t2.timein, timeout=t2.timeout from table1 t1 join 
(select ID, date, min(time) as timein, max(time) as timeout from table2 group by is, date) as t2 on t1.id=t2.id