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所以我想为我的python脚本创建一个case语句,使其更清晰,但没有这样的事情(据我所知),所以我刚刚做了一堆if/else声明。有什么办法可以让这个更清洁?在Python中编写case语句
if (config.dutCardTypes[0] in [6, 7]) and (config.isPrimary) and (config.measPwr): ### Power Measurement for 28nm on Primary Only
if dsppif[dutDevId].pifReadData(0x1e800) == 0x1 :
print "Link Up, Measuring SteadyState Power..."
if (("Sahara Validation" in dsppif[dutDevId].board.description)) :
v, i, pwr = getOnBoardPwr(dsppif[dutDevId],"Sahara Validation")
vdd21A_pwr = pwr["P2V1"]
vdd12A_pwr = pwr["P1V2"]
vdd_pwr = pwr["VDD"]
vdd3v3_pwr = pwr["P3V3"]
elif "Athena" in dsppif[dutDevId].board.description:
if (("Quad A" in dsppif[dutDevId].board.description)) :
v, i, pwr = getOnBoardPwr(dsppif[dutDevId],"Athena Quad A")
vdd21A_pwr = pwr["P2V1_A"] + pwr["P2V1_B"] + pwr["P2V1_C"] + pwr["P2V1_D"] + pwr["P2V1_E"]
vdd12A_pwr = pwr["P1V2_A"] + pwr["P1V2_B"]
vdd_pwr = pwr["VDD"]
elif (("Quad B" in dsppif[dutDevId].board.description)) :
v, i, pwr = getOnBoardPwr(dsppif[dutDevId],"Athena Quad B")
vdd21A_pwr = pwr["P2V1_A"] + pwr["P2V1_B"] + pwr["P2V1_C"] + pwr["P2V1_D"] + pwr["P2V1_E"]
vdd12A_pwr = pwr["P1V2_A"] + pwr["P1V2_B"]
vdd_pwr = pwr["VDD"]
elif (("Quad C" in dsppif[dutDevId].board.description)) :
v, i, pwr = getOnBoardPwr(dsppif[dutDevId],"Athena Quad C")
vdd21A_pwr = pwr["P2V1_A"] + pwr["P2V1_E"]
vdd12A_pwr = pwr["P1V2_A"]
vdd_pwr = pwr["VDD"]
可能的重复[Replacement for switch statement in Python?](http://stackoverflow.com/questions/60208/replacements-for-switch-statement-in-python) – Billy
你可以** 1。**修复您的缩进** 2。**删除不需要的括号。 –
字典。点击此处查看。 http://stackoverflow.com/questions/60208/replacements-for-switch-statement-in-python –