派生表使用GROUP BY

-1

我试图从结果2页不同的表，其中两个具有完全相同的架构和领域这样的组合：派生表使用GROUP BY

select * from 
(select query_type, count(query_type), campaign_id from table1 
UNION ALL 
select query_type, count(query_type), campaign_id from table2 
) derivedTable group by query_type,campaign_id;

但是，我没有收到包含所有结果query_type和campaign_id。有人可以告诉我失踪了吗？

来源

2014-10-02 Saurabh Verma

考虑提供样本数据集和适当的表定义，并在您的问题中添加您的预期结果集 – 2014-10-02 05:35:18

聚合函数必须在同一个查询（或子查询），其中为GROUP BY，所以：

select query_type, count(query_type), campaign_id 
from (
    select query_type, campaign_id from table1 
    UNION ALL 
    select query_type, campaign_id from table2 
) derivedTable 
group by query_type,campaign_id;

因为你的子查询使用聚合函数，但没有GROUP BY，该子查询只返回一行：

select query_type, count(query_type), campaign_id from table1

来源

2014-10-02 05:40:48 Rimas

试试这个

SELECT 
     query_type 
    , campaign_id 
    , COUNT(query_type) 
FROM (
      SELECT 
        query_type 
       , campaign_id 
      FROM table1 
      UNION ALL 
        SELECT 
         query_type 
         , campaign_id 
        FROM table2 
    ) derivedTable 
GROUP BY 
     query_type 
    , campaign_id 
;

OR这样的：如果所述第二表是远程

SELECT 
     query_type 
     , campaign_id 
     , SUM(query_type) 
FROM (
      SELECT 
        query_type 
       , COUNT(query_type) 
       , campaign_id 
      FROM table1 
      GROUP BY 
        query_type 
       , campaign_id 
      UNION ALL 
        SELECT 
         query_type 
         , COUNT(query_type) 
         , campaign_id 
        FROM table2 
        GROUP BY 
         query_type 
         , campaign_id 
    ) derivedTable 
GROUP BY 
     query_type 
    , campaign_id 
;

第二种形式可以是有用的，否则上述的第一个将被简单的。

来源

2014-10-02 05:44:55

派生表使用GROUP BY

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