Java 2d数组程序中的无限循环

程序应该结束并在最后一个问题得到回答后提供正确答案的数量。相反，程序可以回到循环中的最初问题。 “什么是阿拉巴马州的首府”Java 2d数组程序中的无限循环

package exercise09_17; 
import java.util.Scanner; 

public class exercise09_17 { 

    static Scanner input = new Scanner(System.in).useDelimiter("\r\n"); 
    public static void main(String[] args) { 
     int correctAnswer = 0; 
     String [][] grid = { 
       {"Alabama", "California", "Delaware", "Florida", "Georgia", 
       "Hawaii", "Idaho", "Kansas", "Lousiana", "Maryland", "New Mexico", "Oregon", 
       "Pennsylvania", "Rhode Island", "South Carolina", "Texas", "Utah", "Virgina", 
       "West Virginia"}, 
       {"Montgomery", "Sacramento", "Dover", "Tallahassee", "Atlanta", 
       "Honolulu", "Boise", "Topeka", "Baton Rouge", "Annapolis", "San Jose", "Salem", 
       "Harrisburg", "Providence", "Columbia", "Austin", "Salt Lake City", "Richmond", 
       "Charleston"}}; 

     for(int i = 0; i< grid.length; i++){ 

      for(int k = 0; k < grid[i].length; k++){ 
       System.out.println("What is the capital of " + grid[0][k] + "?"); 
       String capital = input.next(); 
       String answer = grid[1][k]; 


       if(capital.equalsIgnoreCase(answer)){ 
       correctAnswer ++; 
       System.out.println("Your answer is correct"); 
       } 
       else 
        System.out.println("The correct answer should be " + answer); 
      } 

     } 
     System.out.println("The correct count is " + correctAnswer); 
    } 
}

来源

2014-02-16 MontyMax

这是不是无限的。这只是因为嵌套的循环而重复。 – Makoto

打印计数的语句位于循环内部。 –

它不是无限的。它只是两次：

for(int i = 0; i< grid.length; i++){

没有必要为这个i变量这里，因此整个外环为好，因为你在第一次就通

使用两个子阵列， grid[0]和 grid[1]

来源

2014-02-16 18:35:13 torquestomp

尝试去除外部for loop：

public class exercise09_17 { 

    static Scanner input = new Scanner(System.in).useDelimiter("\r\n"); 
    public static void main(String[] args) { 
     int correctAnswer = 0; 
     String [][] grid = { 
       {"Alabama", "California", "Delaware", "Florida", "Georgia", 
       "Hawaii", "Idaho", "Kansas", "Lousiana", "Maryland", "New Mexico", "Oregon", 
       "Pennsylvania", "Rhode Island", "South Carolina", "Texas", "Utah", "Virgina", 
       "West Virginia"}, 
       {"Montgomery", "Sacramento", "Dover", "Tallahassee", "Atlanta", 
       "Honolulu", "Boise", "Topeka", "Baton Rouge", "Annapolis", "San Jose", "Salem", 
       "Harrisburg", "Providence", "Columbia", "Austin", "Salt Lake City", "Richmond", 
       "Charleston"}}; 



     for(int k = 0; k < grid[0].length; k++){ 
      System.out.println("What is the capital of " + grid[0][k] + "?"); 
      String capital = input.next(); 
      String answer = grid[1][k]; 


      if(capital.equalsIgnoreCase(answer)){ 
       correctAnswer ++; 
       System.out.println("Your answer is correct"); 
      } else 
       System.out.println("The correct answer should be " + answer); 
     } 

     System.out.println("The correct count is " + correctAnswer); 
    } 
}

来源

2014-02-16 18:35:29

你的代码片段不会编译，因为没有'i'变量，for循环应该有'k torquestomp

这很好。谢谢 –

变化

System.out.println("What is the capital of " + grid[0][k] + "?");

到

System.out.println("What is the capital of " + grid[i][k] + "?");

你通过所有K迭代去后使用grid[0][k]因为它会回来对同一i=0另一个ķ迭代直到i<grid.length

来源

2014-02-16 18:35:34

你没有一个无限循环，但是，你会重复该过程的次数与网格长度一样多。基本上，你不需要外循环。取下环

for(int i = 0; i < grid.length; i++)

和替代

for(int k = 0; k < grid[i].length; k++){

变化

for(int k = 0; k < grid[0].length; k++){

来源

2014-02-16 18:42:52

Java 2d数组程序中的无限循环

回答

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