查询与TOP 10类似以选择中间记录？

Question

我有100条记录，其中我可以在查询中使用“TOP 10”选择前10名。同样有什么可以获得20到30的记录？

Answer 1

由于您使用的是SQL Server 2005，因此您可以使用“新”ROW_NUMBER（）函数。这会给你排11〜20：

SELECT Description, Date 
FROM  (SELECT ROW_NUMBER() OVER (ORDER BY Date DESC) 
      AS Row, Description, Date FROM LOG) 
      AS LogWithRowNumbers 
WHERE Row >= 11 AND Row <= 20 

如果你有很多的记录，内部SELECT子句中使用TOP X，因为没有使用返回1000条记录，如果你只可以加快事情有点经历20抢到记录11：

SELECT Description, Date 
FROM  (SELECT TOP 20 ROW_NUMBER() OVER (ORDER BY Date DESC) 
      AS Row, Description, Date FROM LOG) 
      AS LogWithRowNumbers 
WHERE Row >= 11 AND Row <= 20 

Source

Answer 2

您应该使用ROWNUMBER（）用于获取结果集的记录数和过滤它在那里的原因。

SELECT * FROM (SELECT ROW_NUMBER() OVER(ORDER BY name) AS 
rownum, name , age FROM Table) AS Table1 
WHERE rownum >= 2 AND rownum <= 5 

---------------------------- 
rownum  | name | age | 
---------------------------- 
    2  |John | 25 | 
    3  |Adam | 23 | 
    4  |Tom  | 19 | 
    5  |Jame | 22 | 
----------------------------