我有一个表从JSON文件填充,一切工作到目前为止,但我试图跳过名为“member_count”的键值为0的对象。这可能吗?如果key的值为0,如何跳过JSON文件中的对象?
这是代码:
$mygroupstable = $('#my_groups_table');
$.ajax({
url: 'http://testingsite.com/jsondata/mygroups.json',
dataType:'json',
success:function(data){
$.each(data.groups, function(key, val){
$mygroupstable.append('<tr><td><input type="checkbox" class="groupselector" member_count="' + val.member_count + '" value="' + val.value + '" id="' + val.id + '" name="' + val.name + '" group_name="' + val.group_name + '" /></td><td style="width:10px;"></td><td><label for="' + val.id + '">' + val.group_name + '</label></td></tr>');
})
},
});
JSON文件看起来是这样的:
{
"groups": [
{
"id": "data1",
"member_count": "1",
"value": "255",
"name": "data[]",
"group_name": "Group 1"
},
{
"id": "data2",
"member_count": "5",
"value": "256",
"name": "data[]",
"group_name": "Group 2"
},
{
"id": "data3",
"member_count": "4",
"value": "257",
"name": "data[]",
"group_name": "Group 3"
},
{
"id": "data4",
"member_count": "6",
"value": "258",
"name": "data[]",
"group_name": "Group 4"
},
{
"id": "data5",
"member_count": "0",
"value": "259",
"name": "data[]",
"group_name": "Group 5"
}
]}
在这种情况下5组不应该被追加到表。任何帮助深表感谢!!
如果追加之前添加来检查值的关键,如果关键是MEMBER_COUNT? – morissette 2014-10-27 20:49:19
由于我们迭代一个数组,我会使用'index'或'i',所以我不会迷惑自己。我通常离开'key'进行对象迭代。 – PeterKA 2014-10-27 21:02:56