如果值为0，则从数组中的对象中移除属性

Question

如何从对象中移除属性（如果其值为零）？

var row = [{ 
    2013: "0", 
    2014: "0",  
    2015: "95163", 
    carseries: "Sindelfingen" 
},{ 
    2013: "0", 
    2014: "38954", 
    2015: "0", 
    2016: "0", 
    carseries: "Bremen" 
}]; 

输出应该是这样的：

var row = [{ 
    2015: "95163", 
    carseries: "Sindelfingen" 
},{ 
    2014: "38954", 
    carseries: "Bremen" 
}]; 

Answer 1

你需要使用数组迭代器的组合：map，filter和reduce。

function clean(obj) { 
 
    return Object.keys(obj) // get own keys 
 
       .filter(function(key) { // keep non '0' values 
 
       return obj[key] !== '0' 
 
       }) 
 
       .reduce(function(out, key) { // recreate object using filtered keys 
 
       out[key] = obj[key] 
 

 
       return out 
 
       }, {}) 
 
} 
 

 
var row = [{ 
 
    2013: "0", 
 
    2014: "0", 
 
    2015: "95163", 
 
    carseries: "Sindelfingen" 
 
}, { 
 
    2013: "0", 
 
    2014: "38954", 
 
    2015: "0", 
 
    2016: "0", 
 
    carseries: "Bremen" 
 
}]; 
 

 
// apply clean function to each element of initial array 
 
console.log(row.map(clean))

Answer 2

这工作太：

row.forEach(// loop through your array 
    function(element) { 
     for (key in element) { // for every key in the current object 
      if (element[key] === '0') { // if it's valued to '0' 
       delete element[key]; // remove it from the object 
      } 
     } 
    } 

); 

Answer 3

从对象中删除的项目，您可以使用取消，您可以通过使用两个for循环得到你想要的输出=）

var row = [{ 
 
    2013: "0", 
 
    2014: "0",  
 
    2015: "95163", 
 
    carseries: "Sindelfingen" 
 
},{ 
 
    2013: "0", 
 
    2014: "38954", 
 
    2015: "0", 
 
    2016: "0", 
 
    carseries: "Bremen" 
 
}]; 
 

 
for(var i = 0; row[i]; i++){ 
 
    for(var key in row[i]) { 
 
    if(row[i][key] === "0") delete row[i][key]; 
 
    } 
 
} 
 

 
console.log(row);