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Description i am calling images from database , i want to click on particular image to get detailed of that image which i had stored in table .
在一个表格行中,我打印所有图像,并给出onclick“alert(”)这里我得到了我单击的图像的id。所以如何通过变量,我正在图像点击到其他页面从数据库(这样我可以调用从ID的所有细节)。如何获取从数据库调用的可点击图片的变量?
<html><body>
echo"<table>";
echo "<tr>";
echo "<th>"; echo "<h1>";echo"Id";echo "</h1>";echo "</th>";
echo "<th>"; echo "<h1>";echo"Logo of Websites";echo "</h1>";echo "</th>";
echo "<th>"; echo "<h1>";echo"WebSite Name";echo "</h1>";echo "</th>";
echo "<th>"; echo "<h1>";echo"WebSite Link";echo "</h1>";echo "</th>";
echo "<th>"; echo "<h1>";echo"WebSite Rating";echo "</h1>";echo "</th>";
echo "<th>"; echo "<h1>";echo"Rate Here";echo "</h1>";echo "</th>";
echo"</tr>";
while($row = mysqli_fetch_assoc($find_data)){
echo"<tr>";
echo"<td>"; echo $row["id"]; echo"</td>";
?><div name = "ashish"><?php
$idd=$row["id"];?></div><?php
$showLink=$row["game"];
echo"<td>";?> <img src="images\logo\<?php echo $row["votted"];?>" height="100px" weidth="60px" data-toggle="modal" data-target="#myModal" onClick="alert(<?php echo $row['id']; ?>)"> <?php echo"</td>";
echo"<td>"; echo $row["picture"]; echo"</td>";
echo"<td>";?><a href="https://<?php echo $row["game"]?>"> <?php echo $row["game"]; ?></a><?php echo"</td>";
echo"<td>"; echo "Total Rating -> ";echo $row["rating"]; echo "</br>";echo "Total number of People Voted -> ";echo$row["hits"];
echo"</td>";
echo"<td>"; ?><form action='index.php?option=com_content&view=article&id=47' method ='POST' enctype='multipart/form-data' ><input type='submit' value='Rate Here !' name='rateus'/></form><?php echo"</td>";
echo "</tr>";
}
echo"</table>";
</body>
</html>
Description i am calling
图像, 我想点击 特定图像来获得其 我已经存储在表中的图像的详细 。
做相同的,但能够检索ID? –
您可以检索id的值,因此在打印$ id = $ row ['id']时使用 – Sarath
进行选择查询,它将打印1,并且如果我将该id放在拍摄图像比打印id我点击的图像,那么如何检索该ID? –