SQL Oracle查询

Question

我有这个表中的Oracle DDBB

ASSET | LEVELDATA | VALUE 
1  | Super1  | 500 
1  | Super2  | 400 
2  | Super1  | 300 
2  | Super2  | 150 
3  | Super1  | 180 
3  | Super2  | 50 

我需要证明：

ASSET | Super1 | Super2 
1  | 500 |  400 
2  | 300 |  150 
3  | 180 |  50 

帮助请！感谢

Answer 1

你需要转动操作此处描述：http://www.oracle.com/technetwork/articles/sql/11g-pivot-097235.html

Answer 2

select * 
from 
    (select ASSET 
    from tablename) 
    pivot 
    (count(ASSET) 
     for LEVELDATA in ('Super1', 'Super2')); 

Answer 3

select 
    asset, 
    max(case when leveldata = 'Super1' then value end) Super1, 
    max(case when leveldata = 'Super2' then value end) Super2 
from 
    bbdd 
group by 
    asset; 

正如其他人所指出的，可以达到同样的效果与pivot运营商设置：

select * from DDBB 
pivot (sum(value) for leveldata in ('Super1', 'Super2')) 

SQL fiddle