2012-06-08 37 views
0

我想从可定义的日期范围内的5个不同字段中搜索问题代码,然后得到每个返回的问题代码的总和。下面的“我的查询”对每个查询返回的每个问题代码进行求和,但不会将一个查询的总计添加到另一个查询。访问联盟总和查询

SELECT CUSTRAC.PROBLEM_CO, Count(CUSTRAC.PROBLEM_CO) AS CountOfPROBLEM_CO1 
FROM CUSTRAC 
WHERE (((CUSTRAC.DATE_SHIPP) Between [Begin Date] And [End Date])) 
GROUP BY CUSTRAC.PROBLEM_CO, ([custrac].[problem_co]) 
HAVING (((CUSTRAC.PROBLEM_CO)<>"")); 

Union SELECT CUSTRAC.PROB_2, Count(CUSTRAC.PROB_2) AS CountOfPROB_2 
FROM CUSTRAC 
WHERE (((CUSTRAC.DATE_SHIPP) Between [Begin Date] And [End Date])) 
GROUP BY CUSTRAC.PROB_2, ([custrac].[prob_2]) 
HAVING (((CUSTRAC.PROB_2)<>"")); 

Union SELECT CUSTRAC.PROB_3, Count(CUSTRAC.PROB_3) AS CountofPROB_3 
FROM CUSTRAC 
WHERE (((CUSTRAC.DATE_SHIPP) Between [Begin Date] And [End Date])) 
GROUP BY CUSTRAC.PROB_3, ([custrac].[prob_3]) 
HAVING (((CUSTRAC.PROB_3)<>"")); 

Union SELECT CUSTRAC.PROB_4, Count(CUSTRAC.PROB_4) AS CountofPROB_4 
FROM CUSTRAC 
WHERE (((CUSTRAC.DATE_SHIPP) Between [Begin Date] And [End Date])) 
GROUP BY CUSTRAC.PROB_4, ([custrac].[prob_4]) 
HAVING (((CUSTRAC.PROB_4)<>"")); 

UNION SELECT CUSTRAC.PROB_5, Count(CUSTRAC.PROB_5) AS CountofPROB_5 
FROM CUSTRAC 
WHERE (((CUSTRAC.DATE_SHIPP) Between [Begin Date] And [End Date])) 
GROUP BY CUSTRAC.PROB_5, ([custrac].[prob_5]) 
HAVING (((CUSTRAC.PROB_5)<>"")); 
+3

这还没有有效的SQL。 UNION关键字不能是分号后的第一个标记。无论如何,你为什么使用UNION?这删除重复。你想删除重复?我猜不是。 –

+2

我不认为你使用'HAVING'的方式也是有效的。 “HAVING”应该与聚合函数一起使用。 –

+0

我们还要提出这样一个事实,即group by statement在所有五个查询中提到了两次相同的列。 –

回答

0

如果我理解您的需求,这应该得到你在找什么:

SELECT DISTINCT A.ProbCode, SUM(A.ProbCount) AS ProbSum FROM 
(
SELECT CUSTRAC.PROBLEM_CO AS ProbCode, Count(CUSTRAC.PROBLEM_CO) AS ProbCount 
FROM CUSTRAC 
WHERE CUSTRAC.DATE_SHIPP Between [Begin Date] AND [End Date] AND CUSTRAC.PROBLEM_CO <> '' 
GROUP BY CUSTRAC.PROBLEM_CO 

UNION ALL 

SELECT CUSTRAC.PROB_2 AS ProbCode, Count(CUSTRAC.PROB_2) AS ProbCount 
FROM CUSTRAC 
WHERE CUSTRAC.DATE_SHIPP Between [Begin Date] AND [End Date] AND CUSTRAC.PROB_2 <> '' 
GROUP BY CUSTRAC.PROB_2 

UNION ALL 

SELECT CUSTRAC.PROB_3 AS ProbCode, Count(CUSTRAC.PROB_3) AS ProbCount 
FROM CUSTRAC 
WHERE CUSTRAC.DATE_SHIPP Between [Begin Date] AND [End Date] AND CUSTRAC.PROB_3 <> '' 
GROUP BY CUSTRAC.PROB_3 

UNION ALL 

SELECT CUSTRAC.PROB_4 AS ProbCode, Count(CUSTRAC.PROB_4) AS ProbCount 
FROM CUSTRAC 
WHERE CUSTRAC.DATE_SHIPP Between [Begin Date] AND [End Date] AND CUSTRAC.PROB_4 <> '' 
GROUP BY CUSTRAC.PROB_4 

UNION ALL 

SELECT CUSTRAC.PROB_5 AS ProbCode, Count(CUSTRAC.PROB_5) AS ProbCount 
FROM CUSTRAC 
WHERE CUSTRAC.DATE_SHIPP Between [Begin Date] AND [End Date] AND CUSTRAC.PROB_5 <> '' 
GROUP BY CUSTRAC.PROB_5 

) AS A 

GROUP BY ProbCode 
+0

完美的作品。谢谢。 –

+1

@KimKalmbach如果这回答了您的问题,请点击答案旁边的复选标记以接受它。请参阅[如何接受答案](http://meta.stackexchange.com/q/5234/162993)? – LarsTech