2017-10-08 49 views
-1

当我输入36011时,第二个输出的结果是36011而不是11,我确信编译器设置是正确设置的。我真的不知道还有什么要做,我必须使用long long long来完成这个任务,并且当我尝试在我的代码中使用mod函数时,它不适用于我。MOD功能对我来说无法正常工作

#include <iostream> 

using namespace std; 

int main() 
{ 
long long int seconds; 

cin >> seconds; 

long long int minutes = seconds/60; 
long long int hours = minutes/60; 
long long int days = hours/24; 

cout << "Total seconds: " << seconds << endl; 

if(seconds <= 0) 
{ 
    cout << "\nTotal seconds must be greater than zero"; 
} 

else 
{ 
    if(days > 0) 
    { 
     hours %= 24; 
     cout << "\n" << days << " day(s)"; 
    } 
    if(hours > 0) 
    { 
     minutes %= 60; 
     cout << "\n" << hours << " hour(s)"; 
    } 
    if(minutes > 0) 
    { 
     seconds %= 60; 
     cout << "\n" << minutes << " minute(s)"; 
    } 
    if(seconds > 0) 
    { 
     cout << "\n" << seconds << " second(s)"; 
    } 
} 
cout << endl; 

return 0;} 
+1

当你输入'36011'作为'秒',''分钟'变量将保存'600'。因此,当“分钟%= 60”时,“分钟”将保持为“0”。正因为如此,你的'if(minutes> 0){...}'不会被执行,并且不会在'seconds'上执行模运算符。使用调试器非常容易找到,我强烈建议您学习如何操作 – Fureeish

回答

0

您正在计算您的值错误的方式。试试更像这样的代码:

#include <iostream> 

using namespace std; 

int main() 
{ 
    long long int seconds; 
    cin >> seconds; 

    if (seconds <= 0) 
    { 
     cout << "Total seconds must be greater than zero" << endl; 
    } 
    else 
    { 
     cout << "Total seconds: " << seconds << endl; 

     long long int minutes = seconds/60; seconds %= 60; 
     long long int hours = minutes/60; minutes %= 60; 
     long long int days = hours/24; hours %= 24; 

     /* alternatively: 
     long long int days = seconds/86400; seconds %= 86400; 
     long long int hours = seconds/3600; seconds %= 3600; 
     long long int minutes = seconds/60; seconds %= 60; 
     */ 

     if (days > 0) { 
      cout << days << " day(s)" << endl; 
     } 
     if (hours > 0) { 
      cout << hours << " hour(s)" << endl; 
     } 
     if (minutes > 0) { 
      cout << minutes << " minute(s)" << endl; 
     } 
     if (seconds > 0) { 
      cout << seconds << " second(s)" << endl; 
     } 
    } 

    return 0; 
}