嗨,这是我第二次在这个网站发布。我查看了另一篇关于此消息的文章,但无法弄清楚这一点。堆栈溢出调用堆栈#timememoryfunctionlocation 10.0000143728
所以我试图动态填充数据存储在数据库中的下拉框的内容。
我得到的下降在DB(3次),每条记录显示向下以下错误消息
任何帮助,将不胜感激。 感谢
<!DOCTYPE html>
<?php
$con=mysqli_connect("localhost","root","","project1");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// this block would be at the top of your file above the html
$query = "select * from countries";
$country_results = mysqli_query($con,$query);
$number_of_returns = mysqli_num_rows($country_results);
?>
<html>
<head>
<link rel="stylesheet" type="text/css" href="site.css">
</head>
<body>
<h1>Insert Site into DB</h1>
<h2 class="button"><a href=/index.html>Home</a></h2>
<h2 class="button"><a href=/insert.html>add site</a></h2>
<h2 class="button"><a href=/delete.html>delete site</a></h2>
<h2 class="button"><a href=/search.html>search site</a></h2>
<form class="insert" action="insert.php" method="post">
<p>Site Info</p>
Site code:<input type="text" name="site_code"><br>
Site name: <input type="text" name="site_name"><br>
Address: <input type="text" name="site_address"><br>
City:<br>
Postal code: <input type="text" name="site_postalcode"><br>
Province: <select name="province"></select><br>
Country: <select name=”country”>
<?php while (($row = mysqli_fetch_row($country_results)) != null){ ?>
<option value=”<?php echo $row[‘country’];?></option>
<?php } ?>
</select><br>
<p>Site Contact Info</p>
Site contact name: <input type="text" name="site_contact_name"><br>
Phone number 1: <input type="number" name="site_contact_number1"><br>
Phone number 2: <input type="number" name="site_contact_number2"><br>
Email address: <input type="email" name="site_contact_email"><br>
<input type="submit">
</form>
</body>
</html>
你说:“我收到以下错误消息”,但你从来没有说明它实际是什么。 – patricksweeney
堆栈溢出调用堆栈#timememoryfunctionlocation 10.0000143728 –