我想在java中一个非常简单的GUI。 我刚刚创建了一个带按钮的小图形用户界面,当我们点击每个按钮时,它会打开一个网站。在java中的简单GUI问题
所以我必须有3个按钮: 按钮1 = Gmail的 BUTTON2 =谷歌 BUTTON3 =雅虎
当我点击Button1的,有时它会打开Gmail或谷歌或雅虎。 其他按钮的问题也一样。
为什么?
这里是我的代码非常简单:
import java.awt.*;
import java.awt.event.*;
import java.io.*;
import java.util.logging.Level;
import java.util.logging.Logger;
public class Gui extends Frame implements WindowListener,ActionListener {
//TextField text = new TextField(20);
Button a, b, c;
Process p1, p2, p3;
//private int numClicks = 0;
public static void main(String[] args) {
Gui myWindow = new Gui("Miquelon's");
myWindow.setSize(350,100);
myWindow.setVisible(true);
}
public Gui(String title) {
super(title);
setLayout(new FlowLayout());
addWindowListener(this);
a = new Button("Gmail");
b = new Button ("Google");
c = new Button ("Yahooooo");
add(a);
add(b);
add(c);
//add(text);
a.addActionListener(this);
b.addActionListener(this);
c.addActionListener(this);
}
public void actionPerformed(ActionEvent e)
{
try
{
{
p1 = Runtime.getRuntime().exec("cmd /c start https://mail.google.com");
p2 = Runtime.getRuntime().exec("cmd /c start https://google.com");
p3 = Runtime.getRuntime().exec("cmd /c start https://yahoo.com");
}
}
catch (IOException ex)
{
Logger.getLogger(Gui.class.getName()).log(Level.SEVERE, null, ex);
}
}
public void windowClosing(WindowEvent e) {
dispose();
System.exit(0);
}
public void windowOpened(WindowEvent e) {}
public void windowActivated(WindowEvent e) {}
public void windowIconified(WindowEvent e) {}
public void windowDeiconified(WindowEvent e) {}
public void windowDeactivated(WindowEvent e) {}
public void windowClosed(WindowEvent e) {}
}
谢谢
你有没有试着用调试器来运行这一点,看看会发生什么? – 2011-03-16 20:38:55
@Babak,查看actionPerformed事件,你会发现什么是错的 – 2011-03-16 20:43:52
参见Desktop.browse(URL)。打开浏览器比处理流程容易得多。 – 2011-03-16 20:50:21