将DataTable转换为XML文件并反之亦然

Question

我在读取DataTable上的XML文件时遇到问题。最初，我正在写一个Datatable到一个XML文件并保存它。现在，当我想要将XML文件读回DataTable时，它不会发生。

下面的代码是用于写文件：

private void saveAsToolStripMenuItem_Click(object sender, EventArgs e) 
{ 
    if (myDT_For_DGV.Rows.Count != 0) 
    { 
     saveFileDialog1.ShowDialog(); 
     saveFileDialog1.FileName = "checkOutFile.xml"; 
     myDT_For_DGV.TableName = "CheckOutsAndIns"; 
     myDT_For_DGV.WriteXml(saveFileDialog1.FileName, true); 
    } 
    else 
    { 
     MessageBox.Show("Please add licences to DataGridView, you havent added any licences as of now", "Alert"); 
    } 
} 

以及读取文件：

private void openToolStripMenuItem_Click(object sender, EventArgs e) 
{ 
    //write code to open file 
    if (openFileDialog1.ShowDialog() == DialogResult.OK) 
    { 
     //myFile = openFileDialog1.FileName; 
     System.IO.MemoryStream xmlStream = new System.IO.MemoryStream(); 

     xmlStream.Position = 0; 

     myDT_For_DGV.ReadXml(openFileDialog1.FileName); 
     //MessageBox.Show(openFileDialog1.FileName); 
    } 
} 

Answer 1

我修正了它，问题是，tablename是在保存时分配的，而不是在读取时分配的。因此，全球分配表名，这将使其读写毫无问题。

这样的代码会，

myDT_For_DGV.TableName = "CheckOutsAndIns"; 

if (openFileDialog1.ShowDialog() == DialogResult.OK) 
     {    
       myDT_For_DGV.ReadXml(@openFileDialog1.FileName); 
      //MessageBox.Show(openFileDialog1.FileName); 

     } 

//TO WRITE TO XML 
if (myDT_For_DGV.Rows.Count != 0) 
     { 
      saveFileDialog1.ShowDialog(); 
      saveFileDialog1.FileName = "checkOutFile.xml"; 
      myDT_For_DGV.WriteXml(saveFileDialog1.FileName, true); 
     } 

Answer 2

可能更容易只是与更高级别的数据集工作，就像这样：

DataSet dataSet = new DataSet(); 
DataTable dataTable = new DataTable(); 

dataSet.Tables.Add(dataTable); 
// Save to disk 
dataSet.WriteXml(@"C:\MyDataset.xml"); 

// Read from disk 
dataSet.ReadXml(@"C:\MyDataset.xml");