SQL查询查找每个工单的最后关闭seq_id

Question

由于我不擅长编写SQL查询以便寻求帮助。

我有下面给出的数据集。

我需要编写一个查询找到

最后的查询只应与seq_id返回行的“为每个工作单上次关闭seq_id” = 24,28,32 enter image description here

Answer 1

假设你真的表示 “32”，而不是 “31”，然后row_number()是典型的方法：

select t.* 
from (select t.*, 
      row_number() over (partition by workorder_id order by seq_id desc) as seqnum 
     from t 
     where sts = 'Closed' 
    ) t 
where seqnum = 1; 

Answer 2

尝试这种情况：

SELECT sts 
     ,workorder_id 
     ,MAX(SEQ_ID) AS Last_Seq_ID 
FROM mytablename 
WHERE sts = 'Closed' -- Only include Closed records 
GROUP BY sts, workorder_id 
ORDER BY workorder_id -- This line is optional; it will sort your result 

Answer 3

试试这个：

select workorder_id,max(seq_id) as seqid 
from testtable 
where sts='Closed' 
group by workorder_id 

Answer 4

这将工作的32

SELECT workorder_id 
     ,max(seq_id) 
from your_table 
where sts="Closed" 
group by workorder_id