1
我正在尝试这样的内部连接。无法绑定多部分标识符“Reservation.ReservationID”
select R.ReservationID, R.BookingNumber,P.FirstName, P.LastName
from Reservation R inner join PersonName P
on Reservation.ReservationID = PersonName.ResrvationID
我收到的错误为:
Msg 4104, Level 16, State 1, Line 1
The multi-part identifier "Reservation.ReservationID" could not be bound.
Msg 4104, Level 16, State 1, Line 1
The multi-part identifier "PersonName.ResrvationID" could not be bound.
它的工作原理,但有什么区别? – 2010-10-12 12:07:14
@Nadeem:Reservation.ReservationID不存在,因为您使用了“R”。例如,如果你有两次预订,例如? – gbn 2010-10-12 12:09:07
+1为自我加入的东西 – 2010-10-12 12:12:00