在SQL中查询JSON

我试图找到一种查询SQL中查询JSON的方法，类似于查询XML。有任何想法吗？我还没有保存任何数据，所以我非常开放，尽管我已经阅读了保存JSON的最佳方式是使用varchar(max)的列。在SQL中查询JSON

感谢

例子：

比方说，下面的JSON对象存储在一个varchar(max)列，我想查询柱拉出的“成功”标志的所有事务ID =假。

{"TransactionID":"sample string 1","Success":true, 
"Response":"sample string 3","Values":"sample string 4"}

来源

2015-02-24 jharris8567

SQL Server当前没有本机JSON支持，因此您必须将此列作为字符串读入例如C＃，然后将JSON解析为对象（使用JSON库），然后进行处理。 SQL Server（从版本2005和更新版本）具有本机** XML **支持.... – 2015-02-24 15:48:11

谢谢@marc_s。所以我的另一个想法是在插入之前将其转换为XML。有没有一种简单的方法在VB（或C）中将JSON字符串转换为XML？也许这应该是一个完全不同的问题？ – jharris8567 2015-02-24 15:52:19

我记得，有一个在C＃中编写存储过程和/或函数的选项 - 它会很简单:) – Gerino 2015-02-24 15:56:02

道德故事：不要使用SQL来做到这一点。 CLR和JSON包装是要走的路。但如果你真的好奇，你可以做下面的事情。有太多的问题可能发生，很难全部列出。有关该主题的快速谷歌将轻松显示原因。如果你能确保完美地完美形成JSON对象，这可能是你可以研究的东西。也许。不要使用这个。

/* 
JSON to XML Parser TSQL 
Compatibility: TEsted on SQL Server 2014 
Assumptions: -Perfectly formed JSON as declared below. 
       -Charecters for formatting are ok but will be removed 
*/ 

--Imagine @JSONDATA would be the parameter to your function 
DECLARE @JSONDATA VARCHAR(MAX) = '{"transactions":[ 
             {"TransacitonID":"transaction1","Success":true,"Response":"sample string 1","Values":"sample string 1"}, 
             {"TransactionID":"transaction2","Success":false,"Response":"sample string 2","Values":"sample string 2"} 
           ]}' 

DECLARE @ObjectArrayNameStart INT 
DECLARE @ObjectArrayNameEnd INT 
DECLARE @ObjectArray VARCHAR(MAX) 
DECLARE @ObjectArrayName VARCHAR(MAX) 
DECLARE @ObjectArrayBracketStart INT 
DECLARE @ObjectArrayBracketEnd INT 
DECLARE @ObjectArraySingleton VARCHAR(MAX) 
DECLARE @ObjectXML XML 



--Replace All CR and LF charecters and HT chars 
SET @JSONDATA = REPLACE(REPLACE(REPLACE(@JSONDATA,CHAR(10),''),CHAR(13),''),CHAR(9),'') --LF 

--Get the ObjectArrayName 
SELECT @ObjectArrayNameStart = PATINDEX('%{["]transactions["]:[[]%',@JSONDATA), @ObjectArrayNameEnd = PATINdEX('%[[]%',@JSONDATA) 
SET @ObjectArrayName = SUBSTRING(@JSONDATA,@ObjectArrayNameStart,@ObjectArrayNameEnd) 

--Get the ObjectArray name 
SET @ObjectArray = REPLACE(@JSONDATA,@ObjectArrayName,'') 

----Trim out the word of the object array and get the single word and singleton item 
SET @ObjectArrayName = LEFT(@ObjectArrayName,@ObjectArrayNameEnd - 3) 
SET @ObjectArrayName = RIGHT(@ObjectArrayName, LEN(@ObjectArrayName) - 2) 
SET @ObjectArraySingleton = 'node' 

--PREP THE JSON OBJECT DOWN TO INDIVIDUAL OBJECTS AND SET AS XML DOCUMENT 
SET @ObjectArray = LTRIM(RTRIM(REPLACE(@ObjectArray,']}',''))) 
SET @ObjectArray = REPLACE(@ObjectArray,'},{','</' + @ObjectArraySingleton + '><' + @ObjectArraySingleton + '>') 
SET @ObjectArray = REPLACE(@ObjectArray,'{','<' + @ObjectArraySingleton + '>') 
SET @ObjectArray = REPLACE(@ObjectArray,'}','</' + @ObjectArraySingleton + '>') 
SET @ObjectArray = '<root>' + @ObjectArray + '</root>' 
SET @ObjectXML = CAST(@ObjectArray AS XML) 

--Query for line data 
;WITH XMLObjectData AS (
    SELECT Item.value('text()[1]','nvarchar(max)') AS ObjectLine 
    FROM @ObjectXML.nodes('/root/node') AS Items(Item) 
), CommaSplit AS (
    SELECT '<pair><key>' + REPLACE(X.ObjectLine,',','</value></pair><pair><key>') + '</value></pair>' AS ObjectLine 
    FROM XMLObjectData AS X 
), ColonSplit AS (
    SELECT REPLACE(X.ObjectLine,':','</key><value>') AS ObjectLine 
    FROM CommaSplit AS X 
), QuoteReplace AS (
    SELECT REPLACE(X.ObjectLine,'"','') AS ObjectLine 
    FROM ColonSplit AS X 
) 
SELECT CAST(F.ObjectLine AS XML) 
FROM QuoteReplace AS F 
FOR  XML PATH('object'), ROOT('root') 


--COMMENTED OUT FOR TESTING 
--SELECT @JSONDATA AS JSONData, 
--  @ObjectArrayName AS ObjArrayName, 
--  @ObjectArrayNameStart AS ObjArrayNameStart, 
--  @ObjectArrayNameEnd AS ObjArrayNameEnd, 
--  @ObjectArray AS ObjArray, 
--  @ObjectArraySingleton AS ObjSingleton 
--  --,CAST(@ObjectArray AS XML) AS XMLObjectArray

来源

2015-03-24 22:56:45

在SQL中查询JSON

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