在python，C++中解析文本文件，给出特定格式

Question

我有一个文件格式如下：我想在pyhton和C++中解析它，并在ImpVarNo之后提取数字： 这种格式有很多行。

sample.txt的

Start: 
abc pqr 
(FF_GGGGG_CONFIRM_TR):TC:20222,SeqNum:86,ImpVarNo:1000000008234436,Id:12,oneId:66454,a/c:1,ImpValue:905,Impvar:25,actualValue:905,actualVar:25,abc pqr xyz 
Impquantity:0,pgb ncr yepp 
Start: 
abc pqr 
(FF_GGGGG_CONFIRM_TR):TC:20222,SeqNum:86,ImpVarNo:1000000008234436,Id:12,oneId:66454,a/c:1,ImpValue:905,Impvar:25,actualValue:905,actualVar:25,abc pqr xyz 
Impquantity:0,pgb ncr yepp 
Start: 
abc pqr 
(FF_GGGGG_CONFIRM_TR):TC:20222,SeqNum:86,ImpVarNo:1000000008234436,Id:12,oneId:66454,a/c:1,ImpValue:905,Impvar:25,actualValue:905,actualVar:25,abc pqr xyz 
Impquantity:0,pgb ncr yepp 
Start: 
abc pqr 
(FF_GGGGG_CONFIRM_TR):TC:20222,SeqNum:86,ImpVarNo:1000000008234436,Id:12,oneId:66454,a/c:1,ImpValue:905,Impvar:25,actualValue:905,actualVar:25,abc pqr xyz 
Impquantity:0,pgb ncr yepp 

所以我写了下面的代码：

#!/usr/bin/env python 

import sys 
import re 

hand = open('newlogfile.txt') 
for line in hand: 
    r = re.compile("ExOrderNo:(\d+),") 
    print r 

Answer 1

然而，这是最微不足道的方法，你可以用RegEx使你的代码更干净。

sample_file = open(sample.txt) 
contents = sample_file.readlines() 
for line in contents: 
    if line.startswith("(FF_GGGGG_CONFIRM_TR)"): 
     number_after_impvarno = int(line.split(",")[2][9:]) 

Answer 2

import re 
with open('newlogfile.txt') as f: 
    r = re.compile("ImpVarNo:(\d+),") 
    for line in f: 
     inp = r.findall(line) 
     if inp: 
      print(float(inp[0])) 

1000000008234436 
1000000008234436 
1000000008234436 
1000000008234436 

如果该行总是以同样的事情开始：

import re 
    with open('newlogfile.txt') as f: 
     r = re.compile("ImpVarNo:(\d+),") 
     for line in f: 
      if line.startswith("(FF_GGGGG_CONFIRM_TR)"): 
       print(r.findall(line))