我试图增加一些数组值:递增数组值 - 的Arduino
int counter[] = {0,0,0,0,0,0,0,0};
如果数字的位置0的值达到25,然后在1位的值被加1,并且位置0重置为0.依此类推 - 当索引位置2达到25时,它将位置3增加1,并将其自己的值重置为0.
我正在做一些base26增量 - 生成所有字母组合给定数量的字母。理想情况下,我希望这可以无限工作(理论上) - 当最后一个值达到25时,会添加一个新的数组索引。
我正在处理上一个问题涉及的项目 - 可能会清理我“M试图做:Every permutation of the alphabet up to 29 characters?
下面是我在一分钟代码:
// Set the variables.
String neologism;
int counter[] = {0,0,0,0,0,0,0,0};
String base26[] = {"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"};
void setup() {
// Initialize serial communication:
Serial.begin(9600);
}
void loop() {
int i = 0;
// Reset or increment the counter.
if (counter[i] == 25) {
counter[i] = 0;
counter[i+1]++;
}
else {
counter[i]++;
}
neologism = letters(counter[i]);
Serial.print(neologism+'\n');
delay(100);
i++;
if(i>7) {
i=0;
}
}
String letters(int counter) {
String newword;
for(int i=0; i <= 7; i++) {
newword += base26[counter];
}
return newword;
}
对不起,我不知道你这个问题就在这里。 – 2011-05-08 20:10:23