mysql - 想要在IN子查询中使用LIMIT，如何解决？

我有一个查询是这样的：mysql - 想要在IN子查询中使用LIMIT，如何解决？

SELECT order_number,dr_amount FROM data WHERE order_number IN (select order_number from data where dr_machine='KBA R-' && dr_code='Tryckning' && dr_amount IS NOT NULL && dr_amount!=0 group by order_number having count(*)<2) && dr_machine='KBA R-' && dr_code='Tryckning' && dr_date>='1381442400' && id>'397433' && order_number!='16952' ORDER BY id limit 1;

的结果是这样的：

+--------------+-----------+ 
| order_number | dr_amount | 
+--------------+-----------+ 
|  17047 | 1307  | 
+--------------+-----------+

这就是结果，我想进一步处理。现在我想为此添加一个子查询。我需要检查DATA WHERE oi_amount> 0中的order_number（17047）。所以我尽量让查询此：

SELECT order_number,dr_amount FROM data WHERE order_number IN (select order_number from data where dr_machine='KBA R-' && dr_code='Tryckning' && dr_amount IS NOT NULL && dr_amount!=0 group by order_number having count(*)<2) && dr_machine='KBA R-' && dr_code='Tryckning' && dr_date>='1381442400' && id>'397433' && order_number!='16952' && order_number in (select order_number from data where oi_amount>0) ORDER BY id limit 1;

但是，这给了我：

+--------------+-----------+ 
| order_number | dr_amount | 
+--------------+-----------+ 
|  17046 | 653  | 
+--------------+-----------+

而且这不是我想要的。我想返回没有结果从该查询，因为order_number 17047有oi_amount < = 0（或NULL）据我所知，当order_number 17047不匹配，然后跳到匹配的下一行，这是order_number 17046. 所以我想与限制1.添加一个子查询像这样：

SELECT order_number,dr_amount FROM data WHERE order_number IN (select order_number from data where dr_machine='KBA R-' && dr_code='Tryckning' && dr_amount IS NOT NULL && dr_amount!=0 group by order_number having count(*)<2) && order_number in (select order_number from data where dr_machine='KBA R-' && dr_code='Tryckning' && dr_date>='1381442400' && id>'397433' && order_number!='16952' ORDER BY id limit 1);

但抛出的错误：

This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery'

我的表看起来像这样：

+--------+--------------+-------------+------------+------------+-----------+-----------+ 
| id  | order_number | dr_worker | dr_code | dr_machine | dr_amount | oi_amount | 
+--------+--------------+-------------+------------+------------+-----------+-----------+ 
| 332144 |  16952 | NULL  | NULL  | NULL  | NULL  | 2000  | 
| 397432 |  16952 | Gustafsson, | Intag  | KBA R-  | 1   | NULL  | 
| 397433 |  16952 | Gustafsson, | Tryckning | KBA R-  | 1307  | NULL  | 
| 397434 |  17047 | Gustafsson, | Intag  | KBA R-  | 1   | NULL  | 
| 397435 |  17047 | Gustafsson, | Tryckning | KBA R-  | 1307  | NULL  | 
+--------+--------------+-------------+------------+------------+-----------+-----------+

正如你所看到的order_number 17047没有记录oi_amount，这就是为什么我想返回没有结果/空结果。

我对如何使用JOIN知之甚少，但也许这就是要走的路？我试过索姆查询，但我不知道这甚至会工作（我所有的问题与JOIN有一些语法错误，所以我放弃了）

问候尼克拉斯

来源

2014-10-07 Niclas

我想问你在查询那张表的内容？你想总结order_no的每一个dr_amount吗？因为答案很可能对你有所帮助，但是应该有一个更简单的解决方案来解决你的问题 – Najzero 2014-10-07 11:30:19

最后，我正在寻找dr_code = Tryckning && dr_machine = KBA R-的行，并且“dr_amount与下面的行/下一个”。但结果必须也有oi_amount> 0 – Niclas 2014-10-07 11:36:55

尝试使用join而不是：

SELECT order_number, dr_amount 
FROM data d join 
    (select order_number 
     from data 
     where dr_machine = 'KBA R-' and 
      dr_code = 'Tryckning' and 
      dr_amount IS NOT NULL and 
      dr_amount <> 0 
     group by order_number 
     having count(*) < 2 
    ) i 
    on d.order_number = i.order_number 
WHERE d.dr_machine = 'KBA R-' and 
     d.dr_code = 'Tryckning' and 
     d.dr_date >= '1381442400' and 
     d.id > '397433' and 
     d.order_number <> '16952' 
ORDER BY id 
limit 1;

请注意，我改变了你的运营商，以符合SQL标准：<>代替!=和and，而不是&&。另外，如果看起来像数字的常量确实是数字，则不需要单引号。

来源

2014-10-07 11:27:44

mysql - 想要在IN子查询中使用LIMIT，如何解决？

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