SQL 2012返回次数和两次之间的总和

Question

我之前询问过这个查询，并且我取得了一些进展。现在我需要一个更受限制的数据集，但是我的代码存在问题。下面是我使用的是什么：

DECLARE @mindate DATETIME = '2011-12-30' 
DECLARE @maxdate DATETIME = '2011-12-31' 

;WITH cte 
AS (SELECT 
     CONVERT(DATETIME,@mindate) AS [StartDate], 
     DATEADD(MI, 10,CONVERT(DATETIME,@mindate)) AS [EndDate] 
    UNION ALL 
    SELECT 
     DATEADD(MI, 10, [StartDate]), 
     DATEADD(MI, 10, [EndDate]) 
    FROM cte 
    WHERE [StartDate] < CONVERT(DATETIME,@maxdate)) 

SELECT 
    [StartDate], 
    [EndDate], 
    COUNT(cr.MESSAGE_SIZE) AS [TransactionItemsMigrated], 
    SUM(cr.MESSAGE_SIZE) AS [TransactionSizeBytes], 
    (SELECT COUNT(*) FROM MESSAGE WHERE MESSAGE_STATUS = 2) [CurrentItemsFailed] 
FROM cte 
LEFT JOIN CROSS_REFERENCE cr 
    ON cr.MIGRATION_DATE_TIME BETWEEN [StartDate] AND [EndDate] 
GROUP BY cte.StartDate, cte.EndDate 
OPTION (MAXRECURSION 0) 

我需要显示一排，每10分钟，即使TransactionItemsMigrated和/或TransactionSizeBytes为0或NULL。我得到的结果不会每10分钟显示一次。 StartDate和EndDate之间的时间跨度显示正确，并且似乎正确计数了项目和大小，但StartDate正在跳跃超过10分钟。下面的每个条目都是一行。

StartDate 2016-02-01 00:40:00.000 
EndDate 2016-02-01 00:50:00.000 
TransactionItemsMigrated 1925 
TransactionSizeBytes 1843712 
CurrentItemsFailed 6538601 

StartDate 2016-02-01 01:50:00.000 
EndDate 2016-02-01 02:00:00.000 
TransactionItemsMigrated 1892 
TransactionSizeBytes 51712 
CurrentItemsFailed 6538601 

我无法粘贴结果，因为它在没有复制/粘贴访问权限的虚拟机上运行。有什么建议么？

Answer 1

我可以建议你忘记使用递归来实现你的目标，因为这不会执行，你已经看起来有问题吗？我想用tally table去做。

这是您的脚本使用理货表的翻译。这将表现得更好，同时，它可能会或可能不会解决你的问题，但如果它仍然存在，你一定会对这个问题有更多的了解。

;WITH 
t1  AS (SELECT N = 1 UNION ALL SELECT 1 N), 
t2  AS (SELECT N = 1 FROM t1 x, t1 y), 
t3  AS (SELECT N = 1 FROM t2 x, t2 y), 
t4  AS (SELECT N = 1 FROM t3 x, t3 y), 
t5  AS (SELECT N = 1 FROM t4 x, t4 y), 
Tally AS (SELECT N = ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) 
      FROM t5 AS x, t5 as y)--building a tally with recursive but an less expensive one then the one you had. 

SET DATEFORMAT YMD 
DECLARE @mindate DATETIME = '2011-12-30' 
DECLARE @maxdate DATETIME = '2011-12-31' 
DECLARE @NMax INT 
SELECT @NMax = ISNULL(DATEDIFF(MINUTE, @mindate, @maxdate)/10, 0) --Count the number of 10 minutes slice between the two dates. 

SELECT [StartDate]     = DATEADD(MINUTE, (Tally.N - 1) * 10, @mindate), 
     [EndDate]     = DATEADD(MINUTE, (Tally.N) * 10, @mindate), 
     [TransactionItemsMigrated] = COUNT(cr.MESSAGE_SIZE), 
     [TransactionSizeBytes]  = SUM(cr.MESSAGE_SIZE), 
     [CurrentItemsFailed]  = (SELECT COUNT(*) FROM MESSAGE WHERE MESSAGE_STATUS = 2) 
FROM Tally 
LEFT JOIN CROSS_REFERENCE AS cr ON DATEADD(MINUTE, (Tally.N - 1) * 10, @mindate) >= cr.MIGRATION_DATE_TIME 
           AND DATEADD(MINUTE, (Tally.N) * 10, @mindate) < cr.MIGRATION_DATE_TIME 
WHERE Tally.N <= @NMax 
ORDER BY Tally.N