SimpleAdapter复制项目

Question

我使用SimpleAdapter来显示ListView，但每次按下后退按钮并再次打开活动（显示列表）时，列表中的条目将变为双倍。

如果我再次这样做，数组值再次连接列表中的项目。阵列的

表变量声明为

private static final ArrayList<HashMap<String,String>> list = new ArrayList<HashMap<String,String>>(); 

我的代码中的List.javaonCreate()：

setContentView(R.layout.list); 



    HashMap<String,String> temp = new HashMap<String,String>(); 
    temp.put("first","Strength"); 
    temp.put("second", strength); 
    list.add(temp); 


    HashMap<String,String> temp1 = new HashMap<String,String>(); 
    temp1.put("first","what"); 
    temp1.put("second", "??"); 
    list.add(temp1); 


    HashMap<String,String> temp2 = new HashMap<String,String>(); 
    temp2.put("first","Time"); 
    temp2.put("second", "time"); 
    list.add(temp2); 


    HashMap<String,String> temp3 = new HashMap<String,String>(); 
    temp3.put("first","Repeat"); 
    temp3.put("second", "everyday"); 
    list.add(temp3); 




    setListAdapter(new SimpleAdapter(this,list,R.layout.row_view, new String [] {"first","second"}, new int [] {R.id.rowTextView1, R.id.rowTextView2})); 

Answer 1

你可以做一个if语句来检查，看看是否有什么已经在列表或不是，像这样：

if(list.size() == 0){ 

HashMap<String,String> temp = new HashMap<String,String>(); 
temp.put("first","Strength"); 
temp.put("second", strength); 
list.add(temp); 


HashMap<String,String> temp1 = new HashMap<String,String>(); 
temp1.put("first","what"); 
temp1.put("second", "??"); 
list.add(temp1); 


HashMap<String,String> temp2 = new HashMap<String,String>(); 
temp2.put("first","Time"); 
temp2.put("second", "time"); 
list.add(temp2); 


HashMap<String,String> temp3 = new HashMap<String,String>(); 
temp3.put("first","Repeat"); 
temp3.put("second", "everyday"); 
list.add(temp3); 
}