目前找到的模式后出现的文字,我的Python脚本是这样的:打印随后的组,使用Python
import re
data = open('toy.json', 'r')
for line in data:
m = re.search('\"gas\"', line)
if m:
found = m.group(0)
print(found)
我的数据是这样的(这不是有效的JSON,这是为什么我用regex
)对它进行分析:
{
"blockNumber": "1941794",
"blockHash": "0x41ee74e34cbf9ef4116febea958dbc260e2da3a6bf6f601bfaeb2cd9ab944a29",
"hash": "0xf2b5b8fb173e371cbb427625b0339f6023f8b4ec3701b7a5c691fa9cef9daf63",
"from": "0x3c0cbb196e3847d40cb4d77d7dd3b386222998d9",
"to": "0x2ba24c66cbff0bda0e3053ea07325479b3ed1393",
"gas": "121000",
"gasUsed": "21000",
"gasPrice": "20000000000",
"input": "",
"logs": [],
"nonce": "14",
"value": "0x24406420d09ce7440000",
"timestamp": "2016-07-24 20:28:11 UTC"
}
{
"blockNumber": "1941716",
"blockHash": "0x75e1602cad967a781f4a2ea9e19c97405fe1acaa8b9ad333fb7288d98f7b49e3",
"hash": "0xf8f2a397b0f7bb1ff212b6bcc57e4a56ce3e27eb9f5839fef3e193c0252fab26",
"from": "0xa0480c6f402b036e33e46f993d9c7b93913e7461",
"to": "0xb2ea1f1f997365d1036dd6f00c51b361e9a3f351",
"gas": "121000",
"gasUsed": "21000",
"gasPrice": "20000000000",
"input": "",
"logs": [],
"nonce": "1",
"value": "0xde0b6b3a7640000",
"timestamp": "2016-07-24 20:12:17 UTC"
}
我的脚本输出以下信息:
"gas"
"gas"
但事实上,我想要的东西更类似于此:
...
"hash": "0xf2b5b8fb173e371cbb427625b0339f6023f8b4ec3701b7a5c691fa9cef9daf63",
"gasUsed": "21000",
"hash": "0xf8f2a397b0f7bb1ff212b6bcc57e4a56ce3e27eb9f5839fef3e193c0252fab26"
"gasUsed": "21000"
...
我试图将其更改为输出随后group
,但没有奏效。
你没有在模式中定义任何组,这是它没有工作的原因。 0总是完全匹配,并且在此范围内,您可以通过在模式中使用圆括号来匹配组。 – marekful
谁来定义组? –