PostgreSQL的语法错误达到或接近“其中”

语法错误达到或接近“其中” 5号线：其中拉链在（选择拉链邮政编码其中城市=“萨克拉

，当我尝试运行这段代码。

update listings 
set price = CASE WHEN (listings.price IS NOT NULL) THEN (price * 
(((100+(select price_change from zips where zips.zipcode=listings.zip))/100))) 
where zip in (select zipcode from zips where city = 'Sacramento');

是否有人看到任何容易修复错误？还是我拿出一些垃圾代码？

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2015-04-07 Michael Wood

你并不需要的情况下，你有没有'其他“部分。只需在您的where子句中添加“price is not null”，您就可以摆脱整个“CASE”并使更新更加高效。 –

只是看到更新的答案@a_horse_with_no_name建议被添加:) –

只是其中条款

update listings 
set price = CASE WHEN (listings.price IS NOT NULL) THEN (price * 
(((100+(select price_change from zips where zips.zipcode=listings.zip))/100))) END 
where zip in (select zipcode from zips where city = 'Sacramento');

按@ a_horse_with_no_name的评论之前添加结束关键字

update listings 
set price = (price * (((100+(select price_change from zips where zips.zipcode=listings.zip))/100))) 
where zip in (select zipcode from zips where city = 'Sacramento') and listings.price IS NOT NULL

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2015-04-07 06:46:48

update listings 
set price = CASE WHEN (listings.price IS NOT NULL) THEN (price * 
(((100+(select price_change from zips where zips.zipcode=listings.zip))/100))) 
where zip in (select zipcode from zips where city = 'Sacramento')

删除;请再试一次

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2015-04-07 06:45:22

不是他正在寻找的答案 –

SQL CASE expression需要以END关键字结尾。

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2015-04-07 06:46:05

PostgreSQL的语法错误达到或接近“其中”

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