Django创建模型时出错

Question

我在创建具有外部对象的用户配置文件时遇到问题。

我有一个用户，我想附加一个帐户类型给该用户。

model.py

from __future__ import unicode_literals 

from django.db import models 
from django.contrib.auth.models import User 


class UserProfile(models.Model): 
    user = models.ForeignKey(User, unique=True) 
    account = models.ForeignKey(Account, unique=True) 

class Account(models.Model): 
    reports = models.IntegerField(default=3) 
    accounttype = models.CharField(default='Free', max_length=250) 
    description = models.CharField(default='N/A', max_length=250) 
    monthlycost = models.FloatField(default=0.0) 

    def __str__(self): 
     return self.user.username + " - " + self.accounttype 

的问题是，我发现了以下错误：

account = models.ForeignKey(Account, unique=True) 
NameError: name 'Account' is not defined 

如何呼吁外键Account类？

Answer 1

from __future__ import unicode_literals 

from django.db import models 
from django.contrib.auth.models import User 


class UserProfile(models.Model): 
    user = models.ForeignKey(User, unique=True) 
    account = models.ForeignKey("app_name.Account", unique=True) 

class Account(models.Model): 
    reports = models.IntegerField(default=3) 
    accounttype = models.CharField(default='Free', max_length=250) 
    description = models.CharField(default='N/A', max_length=250) 
    monthlycost = models.FloatField(default=0.0) 

    def __str__(self): 
     return self.user.username + " - " + self.accounttype 

可以使用"app_name.Account"代替Account。将app_name替换为您的应用的名称。

Answer 2

按照约翰·戈登评论，我搬到上面帐户和用户配置它的工作

class Account(models.Model): 
    reports = models.IntegerField(default=3) 
    accounttype = models.CharField(default='Free', max_length=250) 
    description = models.CharField(default='N/A', max_length=250) 
    monthlycost = models.FloatField(default=0.0) 

    def __str__(self): 
     return self.user.username + " - " + self.accounttype 


class UserProfile(models.Model): 
    user = models.ForeignKey(User, unique=True) 
    account = models.ForeignKey(Account, unique=True) 

谢谢你们:)